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marwa.ally

  • 2 years ago

An RC circuit has a time constant of 2.10 s. At t = 0, the capacitor is fully charged. At what time will the energy stored in the capacitor be half of its initial value? Given that: U=q^2/2C q(t)=V*C(1-e^-t/RC)

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  1. arcticf0x
    • 2 years ago
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    how is the capacitor fully charged at t=0, can you somehow verify that?

  2. marwa.ally
    • 2 years ago
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    actually i don't know and i kind of didnt understand what he meant by saying the capacitor is fully charged at t=0 :S

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