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 2 years ago
An RC circuit has a time constant of 2.10 s. At t = 0, the capacitor is fully charged. At what time will the energy stored in the capacitor be half of its initial value?
Given that:
U=q^2/2C
q(t)=V*C(1e^t/RC)
 2 years ago
An RC circuit has a time constant of 2.10 s. At t = 0, the capacitor is fully charged. At what time will the energy stored in the capacitor be half of its initial value? Given that: U=q^2/2C q(t)=V*C(1e^t/RC)

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arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.0how is the capacitor fully charged at t=0, can you somehow verify that?

marwa.ally
 2 years ago
Best ResponseYou've already chosen the best response.0actually i don't know and i kind of didnt understand what he meant by saying the capacitor is fully charged at t=0 :S
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