anonymous
  • anonymous
An RC circuit has a time constant of 2.10 s. At t = 0, the capacitor is fully charged. At what time will the energy stored in the capacitor be half of its initial value? Given that: U=q^2/2C q(t)=V*C(1-e^-t/RC)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
how is the capacitor fully charged at t=0, can you somehow verify that?
anonymous
  • anonymous
actually i don't know and i kind of didnt understand what he meant by saying the capacitor is fully charged at t=0 :S

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