A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
marwa.ally
 3 years ago
An RC circuit has a time constant of 2.10 s. At t = 0, the capacitor is fully charged. At what time will the energy stored in the capacitor be half of its initial value?
Given that:
U=q^2/2C
q(t)=V*C(1e^t/RC)
marwa.ally
 3 years ago
An RC circuit has a time constant of 2.10 s. At t = 0, the capacitor is fully charged. At what time will the energy stored in the capacitor be half of its initial value? Given that: U=q^2/2C q(t)=V*C(1e^t/RC)

This Question is Closed

arcticf0x
 3 years ago
Best ResponseYou've already chosen the best response.0how is the capacitor fully charged at t=0, can you somehow verify that?

marwa.ally
 3 years ago
Best ResponseYou've already chosen the best response.0actually i don't know and i kind of didnt understand what he meant by saying the capacitor is fully charged at t=0 :S
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.