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Hunus

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  • one year ago
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  1. Hunus
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    In a book I'm reading, the author keeps moving quantities to the other side of the differential element. \[ m\vec G \cdot d \vec r = - dU\] He then says to divide by m \[\vec G \cdot d \vec r = -\frac{dU}{m}\]he then says \[\phi = \frac{U}{m}\] so that \[\vec G \cdot \vec r = -d \phi\]

    • one year ago
  2. Hunus
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    Can someone explain this to me?

    • one year ago
  3. hamza_b23
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    alright do you get the first step atleast where he brought the m over?

    • one year ago
  4. hamza_b23
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    i am going to assume you know that because it is a constant and you can divide it if you like the author chooses too thats not important , ok so now to the second line we got G.dr = -dU/m right after what the author did was he took the integral of both sides lets do the left hand side first G.dr the integral of that in respect to r is G.r because dr says we have a function of r. Now lets do the right side-dU/m the integral of that is -U/m, we dont do anything to -1/m because that is just a constant next then he says phi = -U/m where they let G.r=-dphi

    • one year ago
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