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help in wat

use half angle formulas to rewrite \[\sqrt{1-\cos30 degrees/2}\]

\[\sin (\theta/2) = \sqrt{(1-\cos \theta)/2}\]

using that formula o but..

so you can rewrite it as sin(15)

hwo do i get there i cantsee

??

what i mean the answer of the problem i sin 15
how do i get there id ont understand

theta = 30 so theta/2 = 30/2 = 15

can u show that

show what...prove that 30/2 = 15

no the whole process

ok
,..?

and

ok

nee help trig= rewrite this using half angle formula
sqrt{1= \cos 135 degress/2}\]

is that a plus or minus ?

sorry
let me rewrite it

\[rewrtite using half aangle formulas \sqrt{1+ \cos 135 dgrees/2}\]

so that my asnwer
my teacher doesn tlike decimals

hello?

can u show me thewhole process
and ow do is hwo it in fraction

hello

what wre u gonnaa say

need help trig rewrite using half angle idnetities =1-cos210 degress/sin210 degrees

need help trig rewrite using half angle idnetities =1-cos210 degress/sin210 degrees

heloo

\[\rightarrow \frac{1-\cos 210}{\sin 210}\]

yes i know the formula i dont know how to use it

no yes

ok tanks

s o how do i ewrite using half angle idnetities =1-cos210 degress/sin210 degrees

by just saying it equals to 1-cos theta/sin theta

???

umm i already answered you before regarding this question

no i dont grasp it

its what it says n my book

yes it does tan theta /2

hello