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help in wat
use half angle formulas to rewrite \[\sqrt{1-\cos30 degrees/2}\]
\[\sin (\theta/2) = \sqrt{(1-\cos \theta)/2}\]

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Other answers:

using that formula o but..
so you can rewrite it as sin(15)
hwo do i get there i cantsee
??
what i mean the answer of the problem i sin 15 how do i get there id ont understand
theta = 30 so theta/2 = 30/2 = 15
can u show that
show what...prove that 30/2 = 15
no the whole process
well i looked up the half-angle identity for sin (theta/2) **shown above** it matches your expression except you have 30 degrees for the angle
ok ,..?
and
ok
nee help trig= rewrite this using half angle formula sqrt{1= \cos 135 degress/2}\]
is that a plus or minus ?
sorry let me rewrite it
\[rewrtite using half aangle formulas \sqrt{1+ \cos 135 dgrees/2}\]
plus means its the cosine half angle formula take the given angle --> 135 divide it by 2 --> 135/2 = 67.5 answer = cos(67.5)
so that my asnwer my teacher doesn tlike decimals
then write it as a fraction...the main thing is do you get the concept? find appropriate formula , then take half the angle
hello?
can u show me thewhole process and ow do is hwo it in fraction
hello
what wre u gonnaa say
are you serious...i showed you step by step...there is no other process you should have a reference in your book or notes showing the half-angle formulas the fraction would simply be 135/2 http://www.freemathhelp.com/trig-double-angles.html
need help trig rewrite using half angle idnetities =1-cos210 degress/sin210 degrees
need help trig rewrite using half angle idnetities =1-cos210 degress/sin210 degrees
heloo
\[\rightarrow \frac{1-\cos 210}{\sin 210}\]
yes i know the formula i dont know how to use it
please don;t message me the same thing you are posting, thanks and this is different it isn't any of the half-angle formulas
no yes
\[\frac{1-\cos 210}{\sin 210} = \csc 210 - \cot 210\] not sure how else to rewrite it unless you want to use sum/difference formulas
ok tanks
s o how do i ewrite using half angle idnetities =1-cos210 degress/sin210 degrees
by just saying it equals to 1-cos theta/sin theta
???
umm i already answered you before regarding this question
no i dont grasp it
i don't think you can rewrite using half-angle formulas look for yourself...see that the expression does not match any the formulas
its what it says n my book
yes it does tan theta /2
hello
yes i am wrong...my ref sheet has a different but equivalent formula for tangent sorry...hey i learned something anyway, now just take half the angle

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