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pythagoras123
At an art exhibition, there were 280 men and 450 women in Hall A. In Hall B, there were 220 men and 665 women. Some men moved from Hall A to Hall B and some women moved from Hall B to Hall A such that 20% of the people in Hall A and 50% of the people in Hall B are men. How many people are there in Hall B in the end?
I don't know much about art.... but I know what I like... dogs playing poker... dogs playing pool...
help @satellite73
Can't come up with any elegant way to do the question, so we'll just have to stick with good old "take this to be x and that to be y" method. Let the men who moved to hall B be x. Let the women who moved to hall A be y. Now, the population of the rooms is something like, Hall A: 280-x men and 450+y women Hall B: 220+x men and 665-y women Data given: 20% of Hall A are men. 50% of Hall B are women. Each point of data gives one equation in x and y. You get two equations. Solve them and you should be able to find the number of people in Hall B.
so i solved this on the paper and got women=370=y men=75=x 665-370=295 220=75=295 total=590 in B
I got the same result. There were 590 people in hall B at the end.