A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Brian is creating a collage on a piece of cardboard that has an area of 110r3 square centimeters. The collage is covered entirely by pieces of paper that do not overlap. Each piece has an area of √r^5 square centimeters. Use the given information to determine an expression for the total number of pieces of paper used.
Can someone please tel me how I would solve this. Or could you just write this in equation form, I have trouble doing so. Word problems just aren't my best. Please and thank you to whoever is able to help me! :)
anonymous
 4 years ago
Brian is creating a collage on a piece of cardboard that has an area of 110r3 square centimeters. The collage is covered entirely by pieces of paper that do not overlap. Each piece has an area of √r^5 square centimeters. Use the given information to determine an expression for the total number of pieces of paper used. Can someone please tel me how I would solve this. Or could you just write this in equation form, I have trouble doing so. Word problems just aren't my best. Please and thank you to whoever is able to help me! :)

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Does this sound good? Since each piece of paper has the same area ( √r^5 cm^2 ) You need to put √r^5 into exponential notation > √r^5 = r^5/2 This can be thought of in two ways: a) the square root of r taken to the fifth power or b) finding the square root of the fifth power or r. they are equivalent Multiply it by a variable and set it equal to 100r^3 cm^2. N(r^(5/2) ) =100 r^3 N = 100 r63 / (r^(5/2)) = 100 r^(3  (5/2)) = 100r^(1/2) N = 100 r^(1/2) = 100√r
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.