A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
Solve log3x+log9=0. round to nearest hundredth if necessary
a..33
b..04
c.3
d.27
 2 years ago
Solve log3x+log9=0. round to nearest hundredth if necessary a..33 b..04 c.3 d.27

This Question is Closed

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1\[\log(3x)+\log(9)=0 ?\]

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1If that is the right expression use that property I mentioned earlier log(a)+log(b)=log(ab)  log(3x)+log(9)=log(3x*9)=log(27x) So you need to solve the following for x: log(27x)=0

Mattwatson08
 2 years ago
Best ResponseYou've already chosen the best response.0so multiply log(3*9)

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1Yes but you missed the x inside there log(27x)=0 when x= what?

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1I assume the base is 10 so we have \[\log_{10}(27x)=0\] Do you know how to solve for x? do 10^ on both sides

freckles
 2 years ago
Best ResponseYou've already chosen the best response.1\[10^{\log _{10}(27x)}=10^0\] \[27x=1\] Can you finish this ?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.