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Mattwatson08

  • 4 years ago

Solve log3x+log9=0. round to nearest hundredth if necessary a..33 b..04 c.3 d.27

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  1. freckles
    • 4 years ago
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    \[\log(3x)+\log(9)=0 ?\]

  2. Mattwatson08
    • 4 years ago
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    how do i solve

  3. freckles
    • 4 years ago
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    If that is the right expression use that property I mentioned earlier log(a)+log(b)=log(ab) ----------- log(3x)+log(9)=log(3x*9)=log(27x) So you need to solve the following for x: log(27x)=0

  4. Mattwatson08
    • 4 years ago
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    so multiply log(3*9)

  5. freckles
    • 4 years ago
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    Yes but you missed the x inside there log(27x)=0 when x= what?

  6. freckles
    • 4 years ago
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    I assume the base is 10 so we have \[\log_{10}(27x)=0\] Do you know how to solve for x? do 10^ on both sides

  7. Mattwatson08
    • 4 years ago
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    3

  8. freckles
    • 4 years ago
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    \[10^{\log _{10}(27x)}=10^0\] \[27x=1\] Can you finish this ?

  9. Mattwatson08
    • 4 years ago
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    yea

  10. freckles
    • 4 years ago
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    cool! :)

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