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Solve log3x+log9=0. round to nearest hundredth if necessary a..33 b..04 c.3 d.27

Mathematics
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\[\log(3x)+\log(9)=0 ?\]
how do i solve
If that is the right expression use that property I mentioned earlier log(a)+log(b)=log(ab) ----------- log(3x)+log(9)=log(3x*9)=log(27x) So you need to solve the following for x: log(27x)=0

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Other answers:

so multiply log(3*9)
Yes but you missed the x inside there log(27x)=0 when x= what?
I assume the base is 10 so we have \[\log_{10}(27x)=0\] Do you know how to solve for x? do 10^ on both sides
3
\[10^{\log _{10}(27x)}=10^0\] \[27x=1\] Can you finish this ?
yea
cool! :)

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