PatrickJordon

how high is the kite off the ground
Red is kite
ill post image

Delete
Share
This Question is Closed

PatrickJordon

Best Response

You've already chosen the best response.

0

j814wong

Best Response

You've already chosen the best response.

1
\[\tan \theta=opposite/adjacent\] You know that the side adjacent to the angle of 50 degrees is 160 units long so plug that in and solve for the opposite value.

PatrickJordon

Best Response

You've already chosen the best response.

0
can you show

j814wong

Best Response

You've already chosen the best response.

1
\[\tan \theta = opposite/adjacent\]
\[\tan 50 = opposite/160\]
\[(\tan50)(160)=opposite\]
Plug that into the calculator to solve for the opposite value.

PatrickJordon

Best Response

You've already chosen the best response.

0
dont have a calc like tht

PatrickJordon

Best Response

You've already chosen the best response.

0
still confused

PatrickJordon

Best Response

You've already chosen the best response.

0
190.68

j814wong

Best Response

You've already chosen the best response.

1
Yeah

PatrickJordon

Best Response

You've already chosen the best response.

0
tht it?

j814wong

Best Response

You've already chosen the best response.

1
Yep

PatrickJordon

Best Response

You've already chosen the best response.

0
tnx

j814wong

Best Response

You've already chosen the best response.

1
No problem