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PatrickJordon

  • 2 years ago

how high is the kite off the ground Red is kite ill post image

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  1. PatrickJordon
    • 2 years ago
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  2. j814wong
    • 2 years ago
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    \[\tan \theta=opposite/adjacent\] You know that the side adjacent to the angle of 50 degrees is 160 units long so plug that in and solve for the opposite value.

  3. PatrickJordon
    • 2 years ago
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    can you show

  4. j814wong
    • 2 years ago
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    \[\tan \theta = opposite/adjacent\] \[\tan 50 = opposite/160\] \[(\tan50)(160)=opposite\] Plug that into the calculator to solve for the opposite value.

  5. PatrickJordon
    • 2 years ago
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    dont have a calc like tht

  6. j814wong
    • 2 years ago
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    http://web2.0calc.com/ You need a scientific calculator.

  7. PatrickJordon
    • 2 years ago
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    still confused

  8. PatrickJordon
    • 2 years ago
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    190.68

  9. j814wong
    • 2 years ago
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    Yeah

  10. PatrickJordon
    • 2 years ago
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    tht it?

  11. j814wong
    • 2 years ago
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    Yep

  12. PatrickJordon
    • 2 years ago
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    tnx

  13. j814wong
    • 2 years ago
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    No problem

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is replying to Can someone tell me what button the professor is hitting...

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