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anonymous
 4 years ago
Optimization Problem:
Ronnie is designing a poster to contain 50in^2 of printing with margins of 4 inches each at the top and at the bottom and margins of 2 inches at each side. What overall dimensions will minimize the amount of paper used?
anonymous
 4 years ago
Optimization Problem: Ronnie is designing a poster to contain 50in^2 of printing with margins of 4 inches each at the top and at the bottom and margins of 2 inches at each side. What overall dimensions will minimize the amount of paper used?

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kropot72
 4 years ago
Best ResponseYou've already chosen the best response.1Let printing width = w and let printing length = x x * w = 50 w = 50/x Overall area A = (w + 4)(x + 8) Sustituting for w gives: A = (50/x + 4)(x + 8) Multiplying out gives: A = 4x + 400/x + 82 We need to find the value of x that makes A a minimum. Are you following so far?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait, are you sure you got the multiplication right for A? i got something else

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just kidding, i did somethign wrong here

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.1Gr8. To find the value of x to give the minimum value of A we differentiate A with respect to x: dA/dx = 4  400/x^2 Now put the result equal to zero and solve for x: 4  400/x^2 = 0 x^2 = 400/4 = 100 \[x=\sqrt{100}=10\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is the correct answer, thank you sir

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my problem is i can't figure out the relevant equation to derive etc.

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.1So the optimum printing length is 10 inches. The optimum printing width is found from: x * w = 50 10 * w = 50 w = 5 So the optimum overall dimensions will be: Length = (10 + 8) = 18 inches Width = (5 + 4) = 9 inches

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you do another one for me? or just part of it, i have it figured out but the arithmetic was crazy, i had to use wolfram, maybe there was another simpler way?

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.1Do you follow the method to get the overall dimensions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually it's just 5" x 10"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we included the area of the print in the overall dimensions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A = (w + 4)((50/w) + 8) that's print area + margins = overall area

kropot72
 4 years ago
Best ResponseYou've already chosen the best response.1Sorry for error. You are right. Good work :)
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