Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Differentiate, expressing each answer using positive exponents. d) y=(4x^2+3x)^2
 one year ago
 one year ago
Differentiate, expressing each answer using positive exponents. d) y=(4x^2+3x)^2
 one year ago
 one year ago

This Question is Closed

lgbasalloteBest ResponseYou've already chosen the best response.2
you know how to use chain rule right? let u = (4x^2+3x) for a while...to solve for the derivative... \(u^{2} du\) can you do that? use power rule on u..then differentiate the value of u
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
What's U? I see it in my textbook, but I don't understand.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
u is (4x^2 + 3x) i substituted it...we're going to solve the derivative this way (u^2)(du) first..we'll solve for the derivative of u by power rule...
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
@lgbasallote: this is not integration..
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
yeah...but i find it easier using u :C
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
Here's what I wrote: h(x)=4x^2+3x, h'(x)=8x+3, g(x)=x^2 and g'(x)=2x. For some reason I put f'(x)=2(8x+3) as the final answer.
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
Wait. Where'd that comment go. I was working on that...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
derivative of x^2 is 2x^3
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
that's the only problem with your solution...though i do not know how you got the final answer..remember that it's [g'(h(x))][h'(x)]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
raised to 3 mimi :P have you forgotten your power rule /;) a^n = na^(n1)
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
Answer in my textbook is y'=(2(8x+3)/((4x^2+3x)^3)
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
\[y'=2(8x+3)/(4x^2+3x)^3\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
yup seems about right
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
I don't know how to get that...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
(4x^2 +3x)^2..use power rule 2(4x^2 +3x)^3 now take the derivative of 4x^2 + 3x...you get 8x +3 2(4x^2 + 3x)^3 (8x+3) put 4x^2 + 3x in denom... 2(8x+3)/(4x^2+3x)^3 make sense?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
LOL you forgot the 2 this time mimi :PPPP
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
\[y=(4x^2+3x)^{2}\] \[y' = 2(4x^2+3x)^{3}*(8x+3)\] \[y' = \frac{2}{4x^{2}+3x} *(8x+3)=>\frac{2(8x+3)}{4x^{2}+3x}\]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
ahh that's about right :) do you get it now @IsTim ?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
And sorry for the various typos..haven't touched derivivatives in a while..
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
for the benefit of the doubt...i'd like to write what i was starting with u... u^2 (du) derivative of u^2 is 2u^3 du = derivative of (4x^2 + 3x) = 8x + 3 substitute back u to 4x^2 + 3x 2(4x^2 + 3x)^3 (8X + 3) @Mimi_x3
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
lol, compare yoursteps to mine; which one is easier? :P
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
mine had 3 steps..yours had 3 reposts :p
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
just kdding dont kill me
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
lol, pity a poor kid who has not touched derivatives in a LONG time! :P
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
hahaha well considering as you have more medals..ill assume your method was easier :p
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
lol, only 1 medal difference dw. i was so nice that i gave you a free one. :p
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
that's the worst part mine was a pity medal :P
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
aww..i take sympathy to those who uses strange methods. :P
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
=))) it's innovation i tell you :p haha
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
Oh no. Mimi, there's a problem!
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
The exponent of 3 on the denominator that surrounds 4x^2+3x. Where is it?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
Woops, typo, lol..so much typos today sorry
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
i told you if you'd just use my method you wont miss that :P
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
\[y' = 2(4x^2+3x)^{3}*(8x+3)=>2*\frac{1}{(4x^{2}+3x)^{3}} *(8x+3)\] \[=>\frac{2}{(4x^{2}+3x)^{3}} *(8x+3) =>\frac{2(8x+3)}{4x^{2}+3x^{3}} \]
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
haha missed it again :P
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
Man this site should have an editing option!!!!! the last one is: \[\large \frac{2(8x+3)}{(4x^{2}+3x)^{3}} \]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
& igba; it looks like IsTim is learning derivatives so its better not to confuse him with ambiguous methods. :P
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
okay :C i just wanted to share my innovations
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
I don't understand. How?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
Which step you do not understand?
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
When you multiply 8x+3 into the fraction thing, how does the denominator stay the same, but have a exponent of 3? I only have the vaguest idea why.
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
I just know that the denominator is the original function, and it is being multiplied to its deriative.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
remember how \(\large a^{n} = \frac{1}{a^n}\)?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
that is simple algebra..which i do not know how to explain..
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.2
Just think as though it's simple algebra..when you go to the last step..and do it normally as you did in algebra..forget it's the derivative.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
the rules on exponent says that if you have a variable raised to a negative exponent you take it's reciprocal and change the exponent to positive
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.2
i.e. \(\LARGE a^{n} = \frac{1}{a^n}\) and \(\Large \frac{1}{a^{n}} = a^n\)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.