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subtract x^2-1/x^2-x-2 - x-1/x-2

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factorize \[x^2-1\] and \[x^2-x-2\]
so it would be x-1/x-2??
the answer i mean

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Other answers:

no \[x^2-1= (x-1)(x+1)\] and \[x^2-x-2 = x^2 - 2x + x -2 = x(x-2) + 1(x-2)= (x+1)(x-2)\] so your problem is \[{{x^2-1}\over{x^2-x-2}}-{{x-1}\over{x-2}}= {{(x-1)(x+1)}\over{(x+1)(x-2)}} - {{x-1}\over{x-2}} = {{x-1}\over{x-2}}-{{x-1}\over{x-2}}=0\]
so the answer is 0
oh ok it got it!
yeah buddy you were right
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