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sheg Group TitleBest ResponseYou've already chosen the best response.3
factorize \[x^21\] and \[x^2x2\]
 2 years ago

HAYESxELITE Group TitleBest ResponseYou've already chosen the best response.1
so it would be x1/x2??
 2 years ago

HAYESxELITE Group TitleBest ResponseYou've already chosen the best response.1
the answer i mean
 2 years ago

sheg Group TitleBest ResponseYou've already chosen the best response.3
no \[x^21= (x1)(x+1)\] and \[x^2x2 = x^2  2x + x 2 = x(x2) + 1(x2)= (x+1)(x2)\] so your problem is \[{{x^21}\over{x^2x2}}{{x1}\over{x2}}= {{(x1)(x+1)}\over{(x+1)(x2)}}  {{x1}\over{x2}} = {{x1}\over{x2}}{{x1}\over{x2}}=0\]
 2 years ago

HAYESxELITE Group TitleBest ResponseYou've already chosen the best response.1
so the answer is 0
 2 years ago

HAYESxELITE Group TitleBest ResponseYou've already chosen the best response.1
oh ok it got it!
 2 years ago

sheg Group TitleBest ResponseYou've already chosen the best response.3
yeah buddy you were right
 2 years ago
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