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HAYESxELITE Group Title

subtract x^2-1/x^2-x-2 - x-1/x-2

  • 2 years ago
  • 2 years ago

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  1. sheg Group Title
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    factorize \[x^2-1\] and \[x^2-x-2\]

    • 2 years ago
  2. HAYESxELITE Group Title
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    so it would be x-1/x-2??

    • 2 years ago
  3. HAYESxELITE Group Title
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    the answer i mean

    • 2 years ago
  4. sheg Group Title
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    no \[x^2-1= (x-1)(x+1)\] and \[x^2-x-2 = x^2 - 2x + x -2 = x(x-2) + 1(x-2)= (x+1)(x-2)\] so your problem is \[{{x^2-1}\over{x^2-x-2}}-{{x-1}\over{x-2}}= {{(x-1)(x+1)}\over{(x+1)(x-2)}} - {{x-1}\over{x-2}} = {{x-1}\over{x-2}}-{{x-1}\over{x-2}}=0\]

    • 2 years ago
  5. HAYESxELITE Group Title
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    so the answer is 0

    • 2 years ago
  6. HAYESxELITE Group Title
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    oh ok it got it!

    • 2 years ago
  7. sheg Group Title
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    yeah buddy you were right

    • 2 years ago
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