anonymous
  • anonymous
subtract x^2-1/x^2-x-2 - x-1/x-2
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
factorize \[x^2-1\] and \[x^2-x-2\]
anonymous
  • anonymous
so it would be x-1/x-2??
anonymous
  • anonymous
the answer i mean

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anonymous
  • anonymous
no \[x^2-1= (x-1)(x+1)\] and \[x^2-x-2 = x^2 - 2x + x -2 = x(x-2) + 1(x-2)= (x+1)(x-2)\] so your problem is \[{{x^2-1}\over{x^2-x-2}}-{{x-1}\over{x-2}}= {{(x-1)(x+1)}\over{(x+1)(x-2)}} - {{x-1}\over{x-2}} = {{x-1}\over{x-2}}-{{x-1}\over{x-2}}=0\]
anonymous
  • anonymous
so the answer is 0
anonymous
  • anonymous
oh ok it got it!
anonymous
  • anonymous
yeah buddy you were right
anonymous
  • anonymous
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anonymous
  • anonymous
CAN YOU send those guys to my house toooo???? i want a piggy bak ride ??? ;) @stupid12345678910

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