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sheg
 2 years ago
Best ResponseYou've already chosen the best response.3factorize \[x^21\] and \[x^2x2\]

HAYESxELITE
 2 years ago
Best ResponseYou've already chosen the best response.1so it would be x1/x2??

sheg
 2 years ago
Best ResponseYou've already chosen the best response.3no \[x^21= (x1)(x+1)\] and \[x^2x2 = x^2  2x + x 2 = x(x2) + 1(x2)= (x+1)(x2)\] so your problem is \[{{x^21}\over{x^2x2}}{{x1}\over{x2}}= {{(x1)(x+1)}\over{(x+1)(x2)}}  {{x1}\over{x2}} = {{x1}\over{x2}}{{x1}\over{x2}}=0\]
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