anonymous
  • anonymous
30.) Simplify: √18a^2 2a√3 √9a 3a√2 3a√2a 31.) Simplify: 4√5 - 6√3 + 8√5 -2√5 + 8√3 12√5 - 6√3 6√15 6√7 32.) Find the sum of 3√5 and 2√20 7√5 30√2 3√5 + 10√2 60 33.) Find the difference of 9√7 and √28 7√7 11√7 3√5 + 10√2 34.) Simplify: 4√2 + √32 - √16 4√2 + √32 - 4 8√2 - 4 9√2 - 4 4√2 - 16
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Hi @qwertyfreak - please only post one question at a time. Additionally, please at least write out your question, and try and *learn* how to complete them as opposed to simply asking for answers, thank you!
phi
  • phi
Simplify: \( \sqrt{18a^2} \) First, do you know what is the \( \sqrt{a^2} \) ?
anonymous
  • anonymous
no! im in a hurry can i just have the answers pls?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I have 2 leave in 5 mins for work!
anonymous
  • anonymous
@qwertyfreak - Please review OpenStudy's Code of Conduct (openstudy.com/code-of-conduct). OpenStudy is NOT here to provide you with just the answers, sorry. Oh, and @phi - great work there, really like how you (started) to help on this problem ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.