ccsoccerox Given the triangle below, what is sec ∡B? a. 4 sqrt33/33 b. 7/4 c. 4/7 d. 7 sqrt33/33 one year ago one year ago

Sec B = 1/ Cos B and cosB = A/7 so sec B = 7/A where A = $\sqrt{7^2 - 4^2}$