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IsTim Group Title

Determine the equation of the tangent to the curve at a given point. x^2+9y^2=37 (1,2)

  • 2 years ago
  • 2 years ago

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  1. IsTim Group Title
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    I've gotten the slope of -1/18, but I don't know if that's correct. And if so, how do I continue?

    • 2 years ago
  2. IsTim Group Title
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    So, first, dy/dx=-x/dy. I then subbed in (1,2) and got -1/18.

    • 2 years ago
  3. CHAD159753 Group Title
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    Lol uhh so I cant give answers so ill just leave now but what youv done so far is correct :D

    • 2 years ago
  4. IsTim Group Title
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    I don't need the answer. I need to know what my process afterwards should be.

    • 2 years ago
  5. inkyvoyd Group Title
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    What's the derivative?

    • 2 years ago
  6. inkyvoyd Group Title
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    And Chad is in 11th grade, he won't be able to help you

    • 2 years ago
  7. IsTim Group Title
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    1. Derivative is 2x+18y(dy/dx)=0. Right? 2. I figured that out already...

    • 2 years ago
  8. CHAD159753 Group Title
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    lol ink I can give him an answer ;D

    • 2 years ago
  9. inkyvoyd Group Title
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    x^2+9y^2=37 dy/dx 37=dy/dx x^2+dy/dx 9y^2 0=2x+18y dy/dx

    • 2 years ago
  10. inkyvoyd Group Title
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    No, you won't give him the answer he's looking for. THe answer he's looking for is an explanation, because, as everyone knows, it's the explanantion that matters in calc

    • 2 years ago
  11. IsTim Group Title
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    I already have the answer in my textbook and potentially Wolfram Alpha. I need to know how to GET there though.

    • 2 years ago
  12. inkyvoyd Group Title
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    Normally at this point I try to isolate dy/dx for convenience

    • 2 years ago
  13. shruti Group Title
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    from conic section?

    • 2 years ago
  14. inkyvoyd Group Title
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    0=2x+18y dy/dx (-2x)/(18y)=dy/dx x/(-9y)=dy/dx

    • 2 years ago
  15. IsTim Group Title
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    Yeah, I think I did that.It's -x/dy right? @ Shruti: I don't think so...

    • 2 years ago
  16. inkyvoyd Group Title
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    And, my answer agrees with your answer here.

    • 2 years ago
  17. inkyvoyd Group Title
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    Although my work here is moot, because i'm in 9th grade.

    • 2 years ago
  18. IsTim Group Title
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    Ok. Thanks for the help so far.

    • 2 years ago
  19. IsTim Group Title
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    Ok. How would I get to the answer of x+18y-37=0 from knowing that the slope is -1/18?

    • 2 years ago
  20. inkyvoyd Group Title
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    eh?

    • 2 years ago
  21. inkyvoyd Group Title
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    If you had the derivative and wanted to get the original equation?

    • 2 years ago
  22. IsTim Group Title
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    I guess?

    • 2 years ago
  23. IsTim Group Title
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    @shruti By conics did you mean http://www.purplemath.com/modules/circle3.htm

    • 2 years ago
  24. amistre64 Group Title
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    since this is an equation of an ellipse, y can be considered an implicit function of x right?

    • 2 years ago
  25. IsTim Group Title
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    I guess. My notes only reveal the steps. This work is not from a textbook.

    • 2 years ago
  26. IsTim Group Title
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    In fact, it's not even addressed in my textbook. That's strange.

    • 2 years ago
  27. amistre64 Group Title
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    it can be .... to derive implicitly, ignore the form of the variable and treat everything as tho it acted like you normally think of deriving x^2+9y^2=37 ; just derive it all, but dont toss out the derived bits 2x x' + 18y y' = 0 now lets consider this when we derive it with respect to x x' = dx/dx = 1 y' = dy/dx like normal so, lets solve it for y'

    • 2 years ago
  28. inkyvoyd Group Title
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    If you have the derivative, and want to get the original equation, you take the anti-derivative of it

    • 2 years ago
  29. inkyvoyd Group Title
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    If you're asking about taking anti-derivatives (indefinite integrals), and have not yet learned about rieman sums, don't worry about the question

    • 2 years ago
  30. inkyvoyd Group Title
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    Otherwise, I might have to look into it.

    • 2 years ago
  31. IsTim Group Title
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    Y' is -x/dy, which, when we sub in (1,2) is -1/18 right?

    • 2 years ago
  32. dpaInc Group Title
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    yes tim, -1/18 is right

    • 2 years ago
  33. IsTim Group Title
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    What would I do next then?

    • 2 years ago
  34. inkyvoyd Group Title
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    Well, you have a point, and a slope.

    • 2 years ago
  35. inkyvoyd Group Title
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    (1,2) -> point -1/18 -> slope

    • 2 years ago
  36. inkyvoyd Group Title
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    remember, y=mx+b

    • 2 years ago
  37. IsTim Group Title
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    Would I sub those into y=mx+b?

    • 2 years ago
  38. dpaInc Group Title
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    you have slope, you have a point, put it in point slope form...

    • 2 years ago
  39. inkyvoyd Group Title
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    put in the point and the slope, and then you have b

    • 2 years ago
  40. inkyvoyd Group Title
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    then, put in y=mx+b, cept don't put in that point

    • 2 years ago
  41. inkyvoyd Group Title
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    This isn't a calculus problem, this is an algebra problem, :D

    • 2 years ago
  42. IsTim Group Title
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    Sorry, what is point slope form? It's algebra? I must really have been "dumbing" down these years...

    • 2 years ago
  43. inkyvoyd Group Title
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    Ok.

    • 2 years ago
  44. inkyvoyd Group Title
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    There's multiple ways of writing the equation for a line.

    • 2 years ago
  45. inkyvoyd Group Title
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    This is point slope: y-y1=m(x-x1)

    • 2 years ago
  46. inkyvoyd Group Title
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    this is slope intecept: y=mx+b

    • 2 years ago
  47. inkyvoyd Group Title
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    This is standard form: ax+by=c

    • 2 years ago
  48. inkyvoyd Group Title
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    I normally work with slope intercept, because i'm more used to it.

    • 2 years ago
  49. inkyvoyd Group Title
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    However, point slope is the fastest way to go here.

    • 2 years ago
  50. inkyvoyd Group Title
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    y-y1=m(x-x1) (x1,y1)=(1,2) m=-1/18

    • 2 years ago
  51. IsTim Group Title
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    The answer is in the form of ax+by=c I guess, but I am also more familiar with slope intercept.

    • 2 years ago
  52. IsTim Group Title
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    Wait, I already have the slope... I know it is -1/18. But how do I get to x+18y-37?

    • 2 years ago
  53. inkyvoyd Group Title
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    y-1=(-1/18)(x-2) now, just isolate y, and distribute x

    • 2 years ago
  54. inkyvoyd Group Title
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    They have given you the point that the line must pass through, and you have found the slope,

    • 2 years ago
  55. IsTim Group Title
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    Oh. I finally understand. Thank you very much. I will call out again if I need help.

    • 2 years ago
  56. inkyvoyd Group Title
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    Ok. :D

    • 2 years ago
  57. IsTim Group Title
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    Wait, 1 and 2 in y-1=(-1/18)(x-2)/ Shouldn't it be y-2=(-1/18)(x-1)? Because (1,2)?

    • 2 years ago
  58. inkyvoyd Group Title
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    Yes

    • 2 years ago
  59. inkyvoyd Group Title
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    I got it confused myself. xD

    • 2 years ago
  60. IsTim Group Title
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    Why doesn't my answer look like that provided on the sheet, which is x+18y-37?

    • 2 years ago
  61. IsTim Group Title
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    Oh. I figured that out. Sorry.

    • 2 years ago
  62. IsTim Group Title
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    Thank you all for putting forth the effort to assist me.

    • 2 years ago
  63. IsTim Group Title
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    Or at the very least, looking over the question.

    • 2 years ago
  64. inkyvoyd Group Title
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    No problem :)

    • 2 years ago
  65. inkyvoyd Group Title
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    This is good premptive practice for me ;)

    • 2 years ago
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