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Wondermath
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What's the derivative of the following? (I will draw it)
 2 years ago
 2 years ago
Wondermath Group Title
What's the derivative of the following? (I will draw it)
 2 years ago
 2 years ago

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Wondermath Group TitleBest ResponseYou've already chosen the best response.0
dw:1335940380736:dw
 2 years ago

Wondermath Group TitleBest ResponseYou've already chosen the best response.0
is it e^(x/2)ln2
 2 years ago

bmp Group TitleBest ResponseYou've already chosen the best response.3
I think it's only \(\LARGE \frac{e^{x/2}}{2} \) Isn't it? It can be rewritten as e^(x/2)
 2 years ago

Wondermath Group TitleBest ResponseYou've already chosen the best response.0
can u tell me how you got it?
 2 years ago

bmp Group TitleBest ResponseYou've already chosen the best response.3
Rewrite it as \[ e^\frac{x}{2} \]Then the derivative of e^u is e^u u', right? So we have derivative of that = e^(x/2) * d(x/2) = 1/2 :)
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.2
\[\huge (\sqrt{e})^x=(e^{1/2})^x=e^{x/2} \] Apply chain rule to get \[\huge e^{x/2} \over\huge 2 \]
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
\[(\sqrt{e})^{x}=(e ^{1/2})^{x}=e ^{x/2}\]
 2 years ago

nustian Group TitleBest ResponseYou've already chosen the best response.0
dw:1335940696779:dw
 2 years ago

thomas5267 Group TitleBest ResponseYou've already chosen the best response.0
The winner of the LaTeX speed competition is...@bmp ! Congratulations!
 2 years ago

Wondermath Group TitleBest ResponseYou've already chosen the best response.0
thanks guys :)
 2 years ago
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