Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Wondermath

  • 3 years ago

What's the derivative of the following? (I will draw it)

  • This Question is Closed
  1. Wondermath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1335940380736:dw|

  2. Wondermath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is it e^(x/2)ln2

  3. nustian
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1/2e^1/2x

  4. bmp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    I think it's only \(\LARGE \frac{e^{x/2}}{2} \) Isn't it? It can be rewritten as e^(x/2)

  5. Wondermath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can u tell me how you got it?

  6. bmp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Rewrite it as \[ e^\frac{x}{2} \]Then the derivative of e^u is e^u u', right? So we have derivative of that = e^(x/2) * d(x/2) = 1/2 :-)

  7. nbouscal
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\huge (\sqrt{e})^x=(e^{1/2})^x=e^{x/2} \] Apply chain rule to get \[\huge e^{x/2} \over\huge 2 \]

  8. kropot72
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[(\sqrt{e})^{x}=(e ^{1/2})^{x}=e ^{x/2}\]

  9. nustian
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1335940696779:dw|

  10. thomas5267
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The winner of the LaTeX speed competition is...@bmp ! Congratulations!

  11. Wondermath
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks guys :)

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy