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Wondermath Group Title

What's the derivative of the following? (I will draw it)

  • 2 years ago
  • 2 years ago

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  1. Wondermath Group Title
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    |dw:1335940380736:dw|

    • 2 years ago
  2. Wondermath Group Title
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    is it e^(x/2)ln2

    • 2 years ago
  3. nustian Group Title
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    1/2e^1/2x

    • 2 years ago
  4. bmp Group Title
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    I think it's only \(\LARGE \frac{e^{x/2}}{2} \) Isn't it? It can be rewritten as e^(x/2)

    • 2 years ago
  5. Wondermath Group Title
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    can u tell me how you got it?

    • 2 years ago
  6. bmp Group Title
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    Rewrite it as \[ e^\frac{x}{2} \]Then the derivative of e^u is e^u u', right? So we have derivative of that = e^(x/2) * d(x/2) = 1/2 :-)

    • 2 years ago
  7. nbouscal Group Title
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    \[\huge (\sqrt{e})^x=(e^{1/2})^x=e^{x/2} \] Apply chain rule to get \[\huge e^{x/2} \over\huge 2 \]

    • 2 years ago
  8. kropot72 Group Title
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    \[(\sqrt{e})^{x}=(e ^{1/2})^{x}=e ^{x/2}\]

    • 2 years ago
  9. nustian Group Title
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    |dw:1335940696779:dw|

    • 2 years ago
  10. thomas5267 Group Title
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    The winner of the LaTeX speed competition is...@bmp ! Congratulations!

    • 2 years ago
  11. Wondermath Group Title
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    thanks guys :)

    • 2 years ago
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