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badi
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The median of a set of 81 consecutive integers is 45. What is the largest of the given numbers?
 2 years ago
 2 years ago
badi Group Title
The median of a set of 81 consecutive integers is 45. What is the largest of the given numbers?
 2 years ago
 2 years ago

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sheg Group TitleBest ResponseYou've already chosen the best response.1
what do u mean by median???
 2 years ago

badi Group TitleBest ResponseYou've already chosen the best response.0
the middle value of a series of numbers arranged in order of siz
 2 years ago

sheg Group TitleBest ResponseYou've already chosen the best response.1
so it is impossible to find the largest term it can be even 45 or anything greater than 45
 2 years ago

badi Group TitleBest ResponseYou've already chosen the best response.0
that what I thought too acctualy the unswer is 85 I didn't understand this explanation ;Median refers to the middle number in a set of observations. To find the required number divide the number of integers by 2 to find out how many integers are there after the median, then add that number to the median.<br>When 81 is divided by 2 the quotient is 40.<br>Largest number of the given set of numbers = 40 + 45<br> <span style='paddingleft:255px;'>= 85</span>
 2 years ago

sheg Group TitleBest ResponseYou've already chosen the best response.1
no for this one you require all the numbers series then only you can tell exactly otherwise it should be greater than or equal to 45
 2 years ago

sheg Group TitleBest ResponseYou've already chosen the best response.1
yeah thats correct it should be 85 only in question it is given 81 consecutive integers it means that first term should be 4540 = 5 and last term should be 45+40 = 85 so largest term is 85
 2 years ago

sheg Group TitleBest ResponseYou've already chosen the best response.1
any more question???
 2 years ago
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