The median of a set of 81 consecutive integers is 45. What is the largest of the given numbers?

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The median of a set of 81 consecutive integers is 45. What is the largest of the given numbers?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what do u mean by median???
the middle value of a series of numbers arranged in order of siz
so it is impossible to find the largest term it can be even 45 or anything greater than 45

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that what I thought too acctualy the unswer is 85 I didn't understand this explanation ;Median refers to the middle number in a set of observations. To find the required number divide the number of integers by 2 to find out how many integers are there after the median, then add that number to the median.
When 81 is divided by 2 the quotient is 40.
Largest number of the given set of numbers = 40 + 45
= 85
no for this one you require all the numbers series then only you can tell exactly otherwise it should be greater than or equal to 45
yeah thats correct it should be 85 only in question it is given 81 consecutive integers it means that first term should be 45-40 = 5 and last term should be 45+40 = 85 so largest term is 85
thanks
any more question???

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