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anonymous
 4 years ago
The median of a set of 81 consecutive integers is 45. What is the largest of the given numbers?
anonymous
 4 years ago
The median of a set of 81 consecutive integers is 45. What is the largest of the given numbers?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what do u mean by median???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the middle value of a series of numbers arranged in order of siz

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it is impossible to find the largest term it can be even 45 or anything greater than 45

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that what I thought too acctualy the unswer is 85 I didn't understand this explanation ;Median refers to the middle number in a set of observations. To find the required number divide the number of integers by 2 to find out how many integers are there after the median, then add that number to the median.<br>When 81 is divided by 2 the quotient is 40.<br>Largest number of the given set of numbers = 40 + 45<br> <span style='paddingleft:255px;'>= 85</span>

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no for this one you require all the numbers series then only you can tell exactly otherwise it should be greater than or equal to 45

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah thats correct it should be 85 only in question it is given 81 consecutive integers it means that first term should be 4540 = 5 and last term should be 45+40 = 85 so largest term is 85
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