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I am unable to draw me a nice diagram :(

Diagram is not necessary to solve this problem.

What's a circumradius?

@blockcolder: http://mathworld.wolfram.com/Circumradius.html

I think I saw something really similar to this on an AEA paper the other day...

Why can't I solve it? What's making this question so hard to solve?

So far,I got
1/R = (CosA+CosB +CosC-1)/(p_1^-1+p_2^-1+p_3^-1)

This requires some knowledge of certain other identities.

Isn't Law of Sines enough? :D

No

You need things with R (and maybe inradius as well)

I used \[\sin 2A + \sin 2B + \sin 2C = 4 \sin A \sin B \sin C \]

and \[ \large R= \frac {abc}{4 \times Area} \]

Yes, I was wondering about that last one.

I was trying to use like bc = 2R p1

Ohh :( I thought maybe somehow trigonometric conversion will give me an answer, but I was so wrong.

has anyone solved it yet? :)

awesome latex btw @Ishaan94

yeah..you missed something alright ^_~

lol

i think you did something careless in your calculation :P

I forgot the two lol

haha see? :p

You know I would have eliminated the \(p\)'s in the first step itself ;)

|dw:1336017694001:dw|

I can still eliminate them but I am trying to think what I am gonna do after it.

can i show you my solution in messages fowwy? :)

yeah sure

lol :))