• anonymous
Fool's problem of the day, (1) If $$p_1, p_2, p_3$$ are respectively the perpendicular from the vertices of $$\triangle ABC$$ to the opposite sides, then prove that $\hspace{3cm} \frac {\cos A}{p_1} + \frac {\cos B}{p_2} + \frac {\cos C}{p_3} = \frac 1 R$ where $$R$$ is the circumradius of the $$\triangle ABC$$ . Good luck!
Mathematics

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