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20Sin(70)= 18.79385

wait... that doesn't seem right

testingtutor, could you double check that?

20 cosec 70°
?

ya, i think that is it

and turing...

The length 'opposite' is 20, what we are looking for is the hypotenuse

I was not trying to break the CoC, I thought I had explained it....

And we know that's a sine.
\[\sin70 = \frac{20}{Hypotenuse}\]

Hence,
\[Hypotenuse = \frac{20}{sin70}\]

|dw:1335992360468:dw|\[\tan\theta=\frac ab\implies b=\frac a{\tan\theta}\]

and @DoomDude a one-line answer is insufficient here

I chose A, is it wrong

^so that is why you need top check the askers understanding before providing the answer

to check*

ok... will do next time, i was just a bit shocked that I was breaking a rule...

it's okay, just please try a little harder to make it so \(they\) give the correct answer, not you

ok...