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computergeek123

@DoomDude

  • one year ago
  • one year ago

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  1. computergeek123
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    • one year ago
  2. DoomDude
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    20Sin(70)= 18.79385

    • one year ago
  3. DoomDude
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    wait... that doesn't seem right

    • one year ago
  4. DoomDude
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    testingtutor, could you double check that?

    • one year ago
  5. computergeek123
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    20 cosec 70° ?

    • one year ago
  6. DoomDude
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    ya, i think that is it

    • one year ago
  7. DoomDude
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    and turing...

    • one year ago
  8. zepp
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    The length 'opposite' is 20, what we are looking for is the hypotenuse

    • one year ago
  9. DoomDude
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    I was not trying to break the CoC, I thought I had explained it....

    • one year ago
  10. zepp
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    And we know that's a sine. \[\sin70 = \frac{20}{Hypotenuse}\]

    • one year ago
  11. zepp
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    Hence, \[Hypotenuse = \frac{20}{sin70}\]

    • one year ago
  12. TuringTest
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    |dw:1335992360468:dw|\[\tan\theta=\frac ab\implies b=\frac a{\tan\theta}\]

    • one year ago
  13. computergeek123
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    • one year ago
  14. TuringTest
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    and @DoomDude a one-line answer is insufficient here

    • one year ago
  15. DoomDude
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    so, it has to be more than one line? LAST problem she asked I explaind why you would use sin and not cos ect.. gave her this link http://www.mathsisfun.com/sine-cosine-tangent.html and then solved it! She already had that info for this one...

    • one year ago
  16. computergeek123
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    I chose A, is it wrong

    • one year ago
  17. TuringTest
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    ^so that is why you need top check the askers understanding before providing the answer

    • one year ago
  18. TuringTest
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    to check*

    • one year ago
  19. DoomDude
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    ok... will do next time, i was just a bit shocked that I was breaking a rule...

    • one year ago
  20. TuringTest
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    it's okay, just please try a little harder to make it so \(they\) give the correct answer, not you

    • one year ago
  21. DoomDude
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    ok...

    • one year ago
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is replying to Can someone tell me what button the professor is hitting...

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