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\[(a+b)(a-b)=a^2-b^2\]

Now, tell me what you think.

(x-6)(x+6)
x times x = x^2 -6 times 6 = -36

Special form: (a+b)(a-b)=a^2-b^2

just multiply a by the x and 6 than mulitply the 6 by the x and 6

than all you have to do is simplify it

Obviously not typing fast enough to keep up here.....LOL

It can be demonstrated from the form\[(a+b)(a-b)=a^2+\underbrace{[ab-ab]}_0-b^2\]

so x^2+6x-6x-36 someone correct me if I am wrong

you also could just distribute so x(x+6)-6(x+6)

than just get rid of the 6x's and get x^2-36 or x^2+36

(x - 6)(x + 6)
this is the difference of square
\[(x-6)^2\]
\[x^2-12x+36\] thats the answer

x^2 -36

yep my answer of x^2-36 was correct I checked

that would only be the answre if the question is the question was (x-6)^2 @GoldRush18

but thethe question is (x-6)(x+6)

oh ok guess i misinterpreted it