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anonymous
 4 years ago
Can anyone help me???
anonymous
 4 years ago
Can anyone help me???

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk about that because i havent figerd that out my self i am new lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0welcome to open study!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i would i would not say no but im sorry i have no clue how to do anything rite now i would but i do not know how rite now....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its okay, but thanks for putting up the effort!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your welcome any time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but we dont know the values..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Only for the second one lol sorry.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\pm \sqrt{a^2  7^2}\]sq. root a^27^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For the other ones you have to use cos sin and tan

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh okay, so this is all we have to do?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like for a) is it x=+/ sq. root a43 degress

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's what I mean. You have to use cos sin tan SIN COS TAN SOH CAH TOA O=opposite side A=adjacent side H=Hypotnus

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Go learn how to use cos sin and tan.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what do u neeed help with the same thing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know abt them already.. but not sure how to use it here..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you know it already then you would know how to use them exactly. Even with my information that I have you about cos sin and tan GO back to that section and review it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it like sin(43)=x/a>a sin(43)=x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Cos(43)=a/x Adjacent side is a over hypotnus which is x CAH

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0c) use tan d) use sin
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