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brattygirl0962
 2 years ago
Best ResponseYou've already chosen the best response.0idk about that because i havent figerd that out my self i am new lol

math456
 2 years ago
Best ResponseYou've already chosen the best response.1welcome to open study!!

brattygirl0962
 2 years ago
Best ResponseYou've already chosen the best response.0i would i would not say no but im sorry i have no clue how to do anything rite now i would but i do not know how rite now....

math456
 2 years ago
Best ResponseYou've already chosen the best response.1its okay, but thanks for putting up the effort!!

brattygirl0962
 2 years ago
Best ResponseYou've already chosen the best response.0your welcome any time

math456
 2 years ago
Best ResponseYou've already chosen the best response.1but we dont know the values..

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1Only for the second one lol sorry.

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1\[\pm \sqrt{a^2  7^2}\]sq. root a^27^2

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1For the other ones you have to use cos sin and tan

math456
 2 years ago
Best ResponseYou've already chosen the best response.1ohh okay, so this is all we have to do?

math456
 2 years ago
Best ResponseYou've already chosen the best response.1like for a) is it x=+/ sq. root a43 degress

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1That's what I mean. You have to use cos sin tan SIN COS TAN SOH CAH TOA O=opposite side A=adjacent side H=Hypotnus

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1Go learn how to use cos sin and tan.

brattygirl0962
 2 years ago
Best ResponseYou've already chosen the best response.0what do u neeed help with the same thing

math456
 2 years ago
Best ResponseYou've already chosen the best response.1i know abt them already.. but not sure how to use it here..

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1If you know it already then you would know how to use them exactly. Even with my information that I have you about cos sin and tan GO back to that section and review it.

math456
 2 years ago
Best ResponseYou've already chosen the best response.1is it like sin(43)=x/a>a sin(43)=x?

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1Cos(43)=a/x Adjacent side is a over hypotnus which is x CAH
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