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brattygirl0962Best ResponseYou've already chosen the best response.0
idk about that because i havent figerd that out my self i am new lol
 one year ago

math456Best ResponseYou've already chosen the best response.1
welcome to open study!!
 one year ago

brattygirl0962Best ResponseYou've already chosen the best response.0
i would i would not say no but im sorry i have no clue how to do anything rite now i would but i do not know how rite now....
 one year ago

math456Best ResponseYou've already chosen the best response.1
its okay, but thanks for putting up the effort!!
 one year ago

brattygirl0962Best ResponseYou've already chosen the best response.0
your welcome any time
 one year ago

math456Best ResponseYou've already chosen the best response.1
but we dont know the values..
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
Only for the second one lol sorry.
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
\[\pm \sqrt{a^2  7^2}\]sq. root a^27^2
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
For the other ones you have to use cos sin and tan
 one year ago

math456Best ResponseYou've already chosen the best response.1
ohh okay, so this is all we have to do?
 one year ago

math456Best ResponseYou've already chosen the best response.1
like for a) is it x=+/ sq. root a43 degress
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
That's what I mean. You have to use cos sin tan SIN COS TAN SOH CAH TOA O=opposite side A=adjacent side H=Hypotnus
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
Go learn how to use cos sin and tan.
 one year ago

brattygirl0962Best ResponseYou've already chosen the best response.0
what do u neeed help with the same thing
 one year ago

math456Best ResponseYou've already chosen the best response.1
i know abt them already.. but not sure how to use it here..
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
If you know it already then you would know how to use them exactly. Even with my information that I have you about cos sin and tan GO back to that section and review it.
 one year ago

math456Best ResponseYou've already chosen the best response.1
is it like sin(43)=x/a>a sin(43)=x?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
Cos(43)=a/x Adjacent side is a over hypotnus which is x CAH
 one year ago
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