## anonymous 4 years ago Can anyone help me???

1. anonymous

2. anonymous

with

3. anonymous

attached file!

4. anonymous

idk about that because i havent figerd that out my self i am new lol

5. anonymous

lol its okay..

6. anonymous

welcome to open study!!

7. anonymous

i would i would not say no but im sorry i have no clue how to do anything rite now i would but i do not know how rite now....

8. anonymous

its okay, but thanks for putting up the effort!!

9. anonymous

10. anonymous

:)

11. anonymous

Pythagoras!!!

12. anonymous

$x^2 + y^2 = z^2$

13. anonymous

but we dont know the values..

14. anonymous

Only for the second one lol sorry.

15. anonymous

$x^2 + 7^2 = a^2$

16. anonymous

solve for x

17. anonymous

sq. root a-7

18. anonymous

$\pm \sqrt{a^2 - 7^2}$sq. root a^2-7^2

19. anonymous

For the other ones you have to use cos sin and tan

20. anonymous

ohh okay, so this is all we have to do?

21. anonymous

I did b

22. anonymous

23. anonymous

like for a) is it x=+/- sq. root a-43 degress

24. anonymous

That's what I mean. You have to use cos sin tan SIN COS TAN SOH CAH TOA O=opposite side A=adjacent side H=Hypotnus

25. anonymous

Go learn how to use cos sin and tan.

26. anonymous

what do u neeed help with the same thing

27. anonymous

i know abt them already.. but not sure how to use it here..

28. anonymous

If you know it already then you would know how to use them exactly. Even with my information that I have you about cos sin and tan GO back to that section and review it.

29. anonymous

is it like sin(43)=x/a-->a sin(43)=x?

30. anonymous

thanks for part b!!

31. anonymous

Cos(43)=a/x Adjacent side is a over hypotnus which is x CAH

32. anonymous

c) use tan d) use sin

33. anonymous

thank you..

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