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with

attached file!

idk about that because i havent figerd that out my self i am new lol

lol its okay..

welcome to open study!!

its okay, but thanks for putting up the effort!!

your welcome any time

:)

Pythagoras!!!

\[x^2 + y^2 = z^2\]

but we dont know the values..

Only for the second one lol sorry.

\[x^2 + 7^2 = a^2\]

solve for x

sq. root a-7

\[\pm \sqrt{a^2 - 7^2}\]sq. root a^2-7^2

For the other ones you have to use cos sin and tan

ohh okay, so this is all we have to do?

I did b

how about angles?

like for a) is it x=+/- sq. root a-43 degress

Go learn how to use cos sin and tan.

what do u neeed help with the same thing

i know abt them already.. but not sure how to use it here..

is it like sin(43)=x/a-->a sin(43)=x?

thanks for part b!!

Cos(43)=a/x
Adjacent side is a over hypotnus which is x
CAH

c) use tan
d) use sin

thank you..