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math456

Can anyone help me???

  • one year ago
  • one year ago

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  1. math456
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    • one year ago
  2. brattygirl0962
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    with

    • one year ago
  3. math456
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    attached file!

    • one year ago
  4. brattygirl0962
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    idk about that because i havent figerd that out my self i am new lol

    • one year ago
  5. math456
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    lol its okay..

    • one year ago
  6. math456
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    welcome to open study!!

    • one year ago
  7. brattygirl0962
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    i would i would not say no but im sorry i have no clue how to do anything rite now i would but i do not know how rite now....

    • one year ago
  8. math456
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    its okay, but thanks for putting up the effort!!

    • one year ago
  9. brattygirl0962
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    your welcome any time

    • one year ago
  10. math456
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    :)

    • one year ago
  11. Romero
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    Pythagoras!!!

    • one year ago
  12. Romero
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    \[x^2 + y^2 = z^2\]

    • one year ago
  13. math456
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    but we dont know the values..

    • one year ago
  14. Romero
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    Only for the second one lol sorry.

    • one year ago
  15. Romero
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    \[x^2 + 7^2 = a^2\]

    • one year ago
  16. Romero
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    solve for x

    • one year ago
  17. math456
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    sq. root a-7

    • one year ago
  18. Romero
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    \[\pm \sqrt{a^2 - 7^2}\]sq. root a^2-7^2

    • one year ago
  19. Romero
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    For the other ones you have to use cos sin and tan

    • one year ago
  20. math456
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    ohh okay, so this is all we have to do?

    • one year ago
  21. Romero
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    I did b

    • one year ago
  22. math456
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    how about angles?

    • one year ago
  23. math456
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    like for a) is it x=+/- sq. root a-43 degress

    • one year ago
  24. Romero
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    That's what I mean. You have to use cos sin tan SIN COS TAN SOH CAH TOA O=opposite side A=adjacent side H=Hypotnus

    • one year ago
  25. Romero
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    Go learn how to use cos sin and tan.

    • one year ago
  26. brattygirl0962
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    what do u neeed help with the same thing

    • one year ago
  27. math456
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    i know abt them already.. but not sure how to use it here..

    • one year ago
  28. Romero
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    If you know it already then you would know how to use them exactly. Even with my information that I have you about cos sin and tan GO back to that section and review it.

    • one year ago
  29. math456
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    is it like sin(43)=x/a-->a sin(43)=x?

    • one year ago
  30. math456
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    thanks for part b!!

    • one year ago
  31. Romero
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    Cos(43)=a/x Adjacent side is a over hypotnus which is x CAH

    • one year ago
  32. Romero
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    c) use tan d) use sin

    • one year ago
  33. math456
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    thank you..

    • one year ago
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