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Mathematics
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Other answers:

idk about that because i havent figerd that out my self i am new lol
lol its okay..
welcome to open study!!
i would i would not say no but im sorry i have no clue how to do anything rite now i would but i do not know how rite now....
its okay, but thanks for putting up the effort!!
your welcome any time
:)
Pythagoras!!!
\[x^2 + y^2 = z^2\]
but we dont know the values..
Only for the second one lol sorry.
\[x^2 + 7^2 = a^2\]
solve for x
sq. root a-7
\[\pm \sqrt{a^2 - 7^2}\]sq. root a^2-7^2
For the other ones you have to use cos sin and tan
ohh okay, so this is all we have to do?
I did b
how about angles?
like for a) is it x=+/- sq. root a-43 degress
That's what I mean. You have to use cos sin tan SIN COS TAN SOH CAH TOA O=opposite side A=adjacent side H=Hypotnus
Go learn how to use cos sin and tan.
what do u neeed help with the same thing
i know abt them already.. but not sure how to use it here..
If you know it already then you would know how to use them exactly. Even with my information that I have you about cos sin and tan GO back to that section and review it.
is it like sin(43)=x/a-->a sin(43)=x?
thanks for part b!!
Cos(43)=a/x Adjacent side is a over hypotnus which is x CAH
c) use tan d) use sin
thank you..

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