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wcaprar
 2 years ago
Best ResponseYou've already chosen the best response.0Parametric Equation: x=9t, y=6t8 I got dy/dx = \[4/((1/2)t ^{1/2})\] Now I need to find d^2y/dx^2. And I got \[t ^{3/2}/((1/2)t ^{1/2})^3\] But It says that I got it wrong. Where did I go wrong?

dumbcow
 2 years ago
Best ResponseYou've already chosen the best response.1wouldn't dy/dx = 2/3 \[\frac{dy}{dx} = \frac{dy}{dt}*\frac{dt}{dx} = 6*\frac{1}{9} = \frac{2}{3}\]

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.0I would have used substitution t = x/9 then y = 6(x/9)  8 dy/dx = 2/3 then 2nd derivative d^y/dx^2 = 0

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.0How did you get: dy/dx = 4/((1/2)t−1/2)?
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