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Hmm \[\frac{x^3 + 2x-ax^3+b + ax -bx^2}{x^2-1}\]

then?

Divide it by x^2

x^3 - ax^3 = 0
=> a= 1

where did u get tht???????

Ishaan y u divided it by x^2???

Hmm it's the matter of choice angela. I felt dividing it with \(x^2\) would be easier.

Oh sorry, Typo. a=1. not a=0

ohhh i got it -_- silly me....u did tht so u get lim of those who have x in the denom zero right?

Yes. :-)

i actually got the same from wht i did

Ishan can you also help me with my pboelm?

Yeah sure. Vancouver

but...u get infinite lim x->inf(x-ax-b)=0 how did u do it then?

Link Me :D

Iright in your left in open questions ;)

And a=1, b=0 are the solutions

@Ishaan Y I no get it ??????

Ishaan u got a random value of a??? O.o

for* not from

ohhh.....silly me :S :$ :$ got it got it :$:$:$:$

Thank you Ishaan :D

You're Welcome! :D