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candice1

  • 2 years ago

simplify the sum. 1.(8u^3+6u^2+8)+(3u^3-6u+8) simplify the defference. 1. (7w^2-7w-3)-(2w^2+5-2) 2. (8w^2-6w-7)-(3w^2+3w-4) find the GCF of the terms of the polynomial. 1.18x^3+24x^2 CAND SOMEBODY HELP ME PLAESE.!!!!!??//??/

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  1. eSpeX
    • 2 years ago
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    What is it you do not understand? For the first three problems you need only combine like terms and for the last one you find the greatest value they have in common.

  2. candice1
    • 2 years ago
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    imm doin work i have never seen until yesterday lol.

  3. eSpeX
    • 2 years ago
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    I'm sure you understand what "like terms" are, so looking at the problems one at a time, combine all of the like terms, once that is accomplished it will be in its simplified form.

  4. candice1
    • 2 years ago
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    thats it???? okay thanks:)

  5. eSpeX
    • 2 years ago
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    :) You're welcome.

  6. estudier
    • 2 years ago
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    For the GCF, you want the expression that divides both (which is "in" both). You can do it in bits, GCF of 18 and 24? (The biggest number that divides both)

  7. candice1
    • 2 years ago
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    thanks.

  8. estudier
    • 2 years ago
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    Come on, tell me what you get...

  9. candice1
    • 2 years ago
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    24???????????????:(

  10. eSpeX
    • 2 years ago
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    What if you think of it like this: 18x^3 = 2*3*3 x*x*x

  11. candice1
    • 2 years ago
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    immm sorrry! imm very dumb in math.

  12. estudier
    • 2 years ago
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    Well, you can't divide 24 into 18 (you can but the answer wont be an integer). A systematic way to find the GCF is to factor the numbers like this 24/2 = 12, 12/2 = 6, 6/2 = 3 so 24 = 2*2*2*3

  13. estudier
    • 2 years ago
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    Ah, EspeX says the same....

  14. eSpeX
    • 2 years ago
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    @estudier has this well in hand. :)

  15. estudier
    • 2 years ago
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    eSpeX

  16. estudier
    • 2 years ago
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    So 24 = 2*2*2*3 and 18 = 2*3*3 To get the GCF you want to "take out" the bits that are in both. Can you see how?

  17. candice1
    • 2 years ago
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    okay i see what you are saying now.

  18. estudier
    • 2 years ago
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    So for instance there are two 3's in 18 but only one in 24 so you can take out one of them.

  19. candice1
    • 2 years ago
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    okay.

  20. estudier
    • 2 years ago
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    What about the 2's?

  21. estudier
    • 2 years ago
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    r u still there?

  22. estudier
    • 2 years ago
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    I guess not.

  23. candice1
    • 2 years ago
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    is the answer to the problem 6?

  24. candice1
    • 2 years ago
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    lol imm still here i just had to run to the restroom.

  25. estudier
    • 2 years ago
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    That's the correct answer to the GCF of 24 and 18. Now the next bit, we sort of do it the same. What's the bit of x^3 and x^2 that is "in" both?

  26. estudier
    • 2 years ago
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    remember x^3 is x*x*x and x^2 = x*x

  27. candice1
    • 2 years ago
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    are you giving me another math problem to work? lol

  28. estudier
    • 2 years ago
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    It's just the same only with x's instead of 2's or 3's We are still on your original GCF question.

  29. candice1
    • 2 years ago
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    id get it?? write it out for me

  30. estudier
    • 2 years ago
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    Write what ?

  31. candice1
    • 2 years ago
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    what you are saying

  32. estudier
    • 2 years ago
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    I thought that's what I was doing....?

  33. candice1
    • 2 years ago
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    lol seee im totally confused

  34. estudier
    • 2 years ago
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    I think you need to do a bit of studying. Try here http://www.purplemath.com/modules/lcm_gcf.htm Thing is, math builds up in layers, if you don't get a layer, you will just have trouble later on.

  35. candice1
    • 2 years ago
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    true true true. thanks soo much for your help.:)

  36. estudier
    • 2 years ago
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    You can try to keep posting your questions to see if someone will just give you the answer but most people will resist answering questions like the first three.

  37. estudier
    • 2 years ago
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    Anyway, good luck.

  38. candice1
    • 2 years ago
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    thanks.

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