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candice1

simplify the sum. 1.(8u^3+6u^2+8)+(3u^3-6u+8) simplify the defference. 1. (7w^2-7w-3)-(2w^2+5-2) 2. (8w^2-6w-7)-(3w^2+3w-4) find the GCF of the terms of the polynomial. 1.18x^3+24x^2 CAND SOMEBODY HELP ME PLAESE.!!!!!??//??/

  • one year ago
  • one year ago

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  1. eSpeX
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    What is it you do not understand? For the first three problems you need only combine like terms and for the last one you find the greatest value they have in common.

    • one year ago
  2. candice1
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    imm doin work i have never seen until yesterday lol.

    • one year ago
  3. eSpeX
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    I'm sure you understand what "like terms" are, so looking at the problems one at a time, combine all of the like terms, once that is accomplished it will be in its simplified form.

    • one year ago
  4. candice1
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    thats it???? okay thanks:)

    • one year ago
  5. eSpeX
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    :) You're welcome.

    • one year ago
  6. estudier
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    For the GCF, you want the expression that divides both (which is "in" both). You can do it in bits, GCF of 18 and 24? (The biggest number that divides both)

    • one year ago
  7. candice1
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    thanks.

    • one year ago
  8. estudier
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    Come on, tell me what you get...

    • one year ago
  9. candice1
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    24???????????????:(

    • one year ago
  10. eSpeX
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    What if you think of it like this: 18x^3 = 2*3*3 x*x*x

    • one year ago
  11. candice1
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    immm sorrry! imm very dumb in math.

    • one year ago
  12. estudier
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    Well, you can't divide 24 into 18 (you can but the answer wont be an integer). A systematic way to find the GCF is to factor the numbers like this 24/2 = 12, 12/2 = 6, 6/2 = 3 so 24 = 2*2*2*3

    • one year ago
  13. estudier
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    Ah, EspeX says the same....

    • one year ago
  14. eSpeX
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    @estudier has this well in hand. :)

    • one year ago
  15. estudier
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    eSpeX

    • one year ago
  16. estudier
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    So 24 = 2*2*2*3 and 18 = 2*3*3 To get the GCF you want to "take out" the bits that are in both. Can you see how?

    • one year ago
  17. candice1
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    okay i see what you are saying now.

    • one year ago
  18. estudier
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    So for instance there are two 3's in 18 but only one in 24 so you can take out one of them.

    • one year ago
  19. candice1
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    okay.

    • one year ago
  20. estudier
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    What about the 2's?

    • one year ago
  21. estudier
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    r u still there?

    • one year ago
  22. estudier
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    I guess not.

    • one year ago
  23. candice1
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    is the answer to the problem 6?

    • one year ago
  24. candice1
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    lol imm still here i just had to run to the restroom.

    • one year ago
  25. estudier
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    That's the correct answer to the GCF of 24 and 18. Now the next bit, we sort of do it the same. What's the bit of x^3 and x^2 that is "in" both?

    • one year ago
  26. estudier
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    remember x^3 is x*x*x and x^2 = x*x

    • one year ago
  27. candice1
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    are you giving me another math problem to work? lol

    • one year ago
  28. estudier
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    It's just the same only with x's instead of 2's or 3's We are still on your original GCF question.

    • one year ago
  29. candice1
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    id get it?? write it out for me

    • one year ago
  30. estudier
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    Write what ?

    • one year ago
  31. candice1
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    what you are saying

    • one year ago
  32. estudier
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    I thought that's what I was doing....?

    • one year ago
  33. candice1
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    lol seee im totally confused

    • one year ago
  34. estudier
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    I think you need to do a bit of studying. Try here http://www.purplemath.com/modules/lcm_gcf.htm Thing is, math builds up in layers, if you don't get a layer, you will just have trouble later on.

    • one year ago
  35. candice1
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    true true true. thanks soo much for your help.:)

    • one year ago
  36. estudier
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    You can try to keep posting your questions to see if someone will just give you the answer but most people will resist answering questions like the first three.

    • one year ago
  37. estudier
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    Anyway, good luck.

    • one year ago
  38. candice1
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    thanks.

    • one year ago
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