simplify the sum.
1.(8u^3+6u^2+8)+(3u^3-6u+8)
simplify the defference.
1. (7w^2-7w-3)-(2w^2+5-2)
2. (8w^2-6w-7)-(3w^2+3w-4)
find the GCF of the terms of the polynomial.
1.18x^3+24x^2
CAND SOMEBODY HELP ME PLAESE.!!!!!??//??/

- anonymous

- chestercat

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- eSpeX

What is it you do not understand?
For the first three problems you need only combine like terms and for the last one you find the greatest value they have in common.

- anonymous

imm doin work i have never seen until yesterday lol.

- eSpeX

I'm sure you understand what "like terms" are, so looking at the problems one at a time, combine all of the like terms, once that is accomplished it will be in its simplified form.

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- anonymous

thats it???? okay thanks:)

- eSpeX

:) You're welcome.

- anonymous

For the GCF, you want the expression that divides both (which is "in" both).
You can do it in bits, GCF of 18 and 24? (The biggest number that divides both)

- anonymous

thanks.

- anonymous

Come on, tell me what you get...

- anonymous

24???????????????:(

- eSpeX

What if you think of it like this:
18x^3 = 2*3*3 x*x*x

- anonymous

immm sorrry! imm very dumb in math.

- anonymous

Well, you can't divide 24 into 18 (you can but the answer wont be an integer).
A systematic way to find the GCF is to factor the numbers like this
24/2 = 12, 12/2 = 6, 6/2 = 3 so 24 = 2*2*2*3

- anonymous

Ah, EspeX says the same....

- eSpeX

@estudier has this well in hand. :)

- anonymous

eSpeX

- anonymous

So
24 = 2*2*2*3 and
18 = 2*3*3
To get the GCF you want to "take out" the bits that are in both.
Can you see how?

- anonymous

okay i see what you are saying now.

- anonymous

So for instance there are two 3's in 18 but only one in 24 so you can take out one of them.

- anonymous

okay.

- anonymous

What about the 2's?

- anonymous

r u still there?

- anonymous

I guess not.

- anonymous

is the answer to the problem 6?

- anonymous

lol imm still here i just had to run to the restroom.

- anonymous

That's the correct answer to the GCF of 24 and 18.
Now the next bit, we sort of do it the same.
What's the bit of x^3 and x^2 that is "in" both?

- anonymous

remember x^3 is x*x*x and x^2 = x*x

- anonymous

are you giving me another math problem to work? lol

- anonymous

It's just the same only with x's instead of 2's or 3's
We are still on your original GCF question.

- anonymous

id get it?? write it out for me

- anonymous

Write what ?

- anonymous

what you are saying

- anonymous

I thought that's what I was doing....?

- anonymous

lol seee im totally confused

- anonymous

I think you need to do a bit of studying.
Try here http://www.purplemath.com/modules/lcm_gcf.htm
Thing is, math builds up in layers, if you don't get a layer, you will just have trouble later on.

- anonymous

true true true. thanks soo much for your help.:)

- anonymous

You can try to keep posting your questions to see if someone will just give you the answer but most people will resist answering questions like the first three.

- anonymous

Anyway, good luck.

- anonymous

thanks.

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