anonymous
  • anonymous
simplify the sum. 1.(8u^3+6u^2+8)+(3u^3-6u+8) simplify the defference. 1. (7w^2-7w-3)-(2w^2+5-2) 2. (8w^2-6w-7)-(3w^2+3w-4) find the GCF of the terms of the polynomial. 1.18x^3+24x^2 CAND SOMEBODY HELP ME PLAESE.!!!!!??//??/
Mathematics
chestercat
  • chestercat
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eSpeX
  • eSpeX
What is it you do not understand? For the first three problems you need only combine like terms and for the last one you find the greatest value they have in common.
anonymous
  • anonymous
imm doin work i have never seen until yesterday lol.
eSpeX
  • eSpeX
I'm sure you understand what "like terms" are, so looking at the problems one at a time, combine all of the like terms, once that is accomplished it will be in its simplified form.

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anonymous
  • anonymous
thats it???? okay thanks:)
eSpeX
  • eSpeX
:) You're welcome.
anonymous
  • anonymous
For the GCF, you want the expression that divides both (which is "in" both). You can do it in bits, GCF of 18 and 24? (The biggest number that divides both)
anonymous
  • anonymous
thanks.
anonymous
  • anonymous
Come on, tell me what you get...
anonymous
  • anonymous
24???????????????:(
eSpeX
  • eSpeX
What if you think of it like this: 18x^3 = 2*3*3 x*x*x
anonymous
  • anonymous
immm sorrry! imm very dumb in math.
anonymous
  • anonymous
Well, you can't divide 24 into 18 (you can but the answer wont be an integer). A systematic way to find the GCF is to factor the numbers like this 24/2 = 12, 12/2 = 6, 6/2 = 3 so 24 = 2*2*2*3
anonymous
  • anonymous
Ah, EspeX says the same....
eSpeX
  • eSpeX
@estudier has this well in hand. :)
anonymous
  • anonymous
eSpeX
anonymous
  • anonymous
So 24 = 2*2*2*3 and 18 = 2*3*3 To get the GCF you want to "take out" the bits that are in both. Can you see how?
anonymous
  • anonymous
okay i see what you are saying now.
anonymous
  • anonymous
So for instance there are two 3's in 18 but only one in 24 so you can take out one of them.
anonymous
  • anonymous
okay.
anonymous
  • anonymous
What about the 2's?
anonymous
  • anonymous
r u still there?
anonymous
  • anonymous
I guess not.
anonymous
  • anonymous
is the answer to the problem 6?
anonymous
  • anonymous
lol imm still here i just had to run to the restroom.
anonymous
  • anonymous
That's the correct answer to the GCF of 24 and 18. Now the next bit, we sort of do it the same. What's the bit of x^3 and x^2 that is "in" both?
anonymous
  • anonymous
remember x^3 is x*x*x and x^2 = x*x
anonymous
  • anonymous
are you giving me another math problem to work? lol
anonymous
  • anonymous
It's just the same only with x's instead of 2's or 3's We are still on your original GCF question.
anonymous
  • anonymous
id get it?? write it out for me
anonymous
  • anonymous
Write what ?
anonymous
  • anonymous
what you are saying
anonymous
  • anonymous
I thought that's what I was doing....?
anonymous
  • anonymous
lol seee im totally confused
anonymous
  • anonymous
I think you need to do a bit of studying. Try here http://www.purplemath.com/modules/lcm_gcf.htm Thing is, math builds up in layers, if you don't get a layer, you will just have trouble later on.
anonymous
  • anonymous
true true true. thanks soo much for your help.:)
anonymous
  • anonymous
You can try to keep posting your questions to see if someone will just give you the answer but most people will resist answering questions like the first three.
anonymous
  • anonymous
Anyway, good luck.
anonymous
  • anonymous
thanks.

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