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How to find the SUM of the solution of the equation: 8x^2+40x=16x

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8x^2 + 40x = 16x (-16x) 8x^2 + 32x = 0 8x(x + 4) = 0 I'll let you take it from here.
Set 8x = 0 and (x +4) = 0 , then the results add together
Correct, since it asks for the sum. You get two results, one from either factor.

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Other answers:

Thanks! How did you get 32x?
By subtracting 16x from both sides and then grouping like terms. Like this: 8x^2 +40x = 16x 8x^2 +40x -16x = 16x-16x 8x^2 +32x = 0
So you subtracted 16x-16x, do you also subtract 40x-16x? If so, wouldn't that equal 24x?
Yes. Haha thank you for catching that.
haha. It's okay!
So after, do you divide each by 8?
Yeah. I get 8x^2 + 24x = 0 and you can take out a factor of 8x
So the answer would be 3?
Kind of almost.
You get a factor of (x+3) What x makes that factor 0?
you can factor out as 4x(2x+6) then set both to zero and you should end up with x= 0 & x = -3 and add them
So the answer is -3?
That was easy! Thanks you guys!

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