anonymous
  • anonymous
How to find the SUM of the solution of the equation: 8x^2+40x=16x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
8x^2 + 40x = 16x (-16x) 8x^2 + 32x = 0 8x(x + 4) = 0 I'll let you take it from here.
anonymous
  • anonymous
Set 8x = 0 and (x +4) = 0 , then the results add together
anonymous
  • anonymous
Correct, since it asks for the sum. You get two results, one from either factor.

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anonymous
  • anonymous
Thanks! How did you get 32x?
anonymous
  • anonymous
By subtracting 16x from both sides and then grouping like terms. Like this: 8x^2 +40x = 16x 8x^2 +40x -16x = 16x-16x 8x^2 +32x = 0
anonymous
  • anonymous
So you subtracted 16x-16x, do you also subtract 40x-16x? If so, wouldn't that equal 24x?
anonymous
  • anonymous
Yes. Haha thank you for catching that.
anonymous
  • anonymous
Embarassing.
anonymous
  • anonymous
haha. It's okay!
anonymous
  • anonymous
So after, do you divide each by 8?
anonymous
  • anonymous
Yeah. I get 8x^2 + 24x = 0 and you can take out a factor of 8x
anonymous
  • anonymous
So the answer would be 3?
anonymous
  • anonymous
Kind of almost.
anonymous
  • anonymous
You get a factor of (x+3) What x makes that factor 0?
anonymous
  • anonymous
you can factor out as 4x(2x+6) then set both to zero and you should end up with x= 0 & x = -3 and add them
anonymous
  • anonymous
So the answer is -3?
anonymous
  • anonymous
yep
anonymous
  • anonymous
That was easy! Thanks you guys!

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