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8x^2 + 40x = 16x
(-16x)
8x^2 + 32x = 0
8x(x + 4) = 0
I'll let you take it from here.

Set 8x = 0 and (x +4) = 0 , then the results add together

Correct, since it asks for the sum. You get two results, one from either factor.

Thanks! How did you get 32x?

So you subtracted 16x-16x, do you also subtract 40x-16x? If so, wouldn't that equal 24x?

Yes. Haha thank you for catching that.

Embarassing.

haha. It's okay!

So after, do you divide each by 8?

Yeah. I get
8x^2 + 24x = 0
and you can take out a factor of 8x

So the answer would be 3?

Kind of almost.

You get a factor of (x+3)
What x makes that factor 0?

So the answer is -3?

yep

That was easy! Thanks you guys!