countonme123
need help dividing algebra terms
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countonme123
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45 TIMES Xto the fourth power TIMES Y to the fourth power
divided by
15 TIMES Xto the second power TIMES Y to third power
countonme123
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other way 15 on top
pfenn1
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\[45x^{4}y ^{4} \over15x ^{2}y ^{3}\]
precal
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|dw:1336094500078:dw|
precal
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like this?
countonme123
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yes sir
pfenn1
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you mean\[15x ^{2}y ^{3}\over45x ^{4}y ^{4}\]
countonme123
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yes precal has it
pfenn1
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=\[=\left( 15 \over 45 \right)\left( x ^{2} \over x ^{4}\right)\left( y ^{3}\over y ^{4} \right)\]
pfenn1
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Can you simplify it now?
countonme123
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ok 1/3 and x2power
precal
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|dw:1336094724230:dw|
countonme123
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i dont know the last one
precal
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|dw:1336094786772:dw|
cesar2462
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precal is right pfenn1 is dummmm
countonme123
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y to the 1 power?
pfenn1
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remember \[\left( 1 \over x ^{a} \right)=x ^{-a}\]and\[x ^{a}x ^{b}=x ^{a+b}\]
cyanidesandwich
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|dw:1336094932499:dw|
that is how it should look
cesar2462
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they got u pfenn1
pfenn1
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@cesar2462, don't really appreciate the attitude. There are several ways to look at this problem and sometimes different ways can help someone understand it better. We are trying to help people learn, not just get the answer.
countonme123
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@pfenn1 i like the idea how you separate it into sections can you do it again with another problem
pfenn1
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sure
countonme123
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-56 TIMES A 4thpower TIMES X 4thpower
over
-8 TIMES A 3rdpower TIMES X
pfenn1
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\[-56A ^{4}x ^{4}\over -8A ^{3}x\]
cyanidesandwich
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-56A^4X^4/-8A^3X that what you mean?
pfenn1
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Sorry, I had problems with my computer.\[\left( -56 \over-8 \right)\left( A ^{4}\over A^{3} \right)\left( x ^{4}\over x\right)=\]
countonme123
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thank you everyone but this medal goes @pfenn1
pfenn1
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Thanks.
farmdawgnation
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@cesar2462 The attitude is not necessary. If you have nothing nice to say, say nothing at all.
countonme123
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i agree^