Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

need help dividing algebra terms

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

45 TIMES Xto the fourth power TIMES Y to the fourth power divided by 15 TIMES Xto the second power TIMES Y to third power
other way 15 on top
\[45x^{4}y ^{4} \over15x ^{2}y ^{3}\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

|dw:1336094500078:dw|
like this?
yes sir
you mean\[15x ^{2}y ^{3}\over45x ^{4}y ^{4}\]
yes precal has it
=\[=\left( 15 \over 45 \right)\left( x ^{2} \over x ^{4}\right)\left( y ^{3}\over y ^{4} \right)\]
Can you simplify it now?
ok 1/3 and x2power
|dw:1336094724230:dw|
i dont know the last one
|dw:1336094786772:dw|
precal is right pfenn1 is dummmm
y to the 1 power?
remember \[\left( 1 \over x ^{a} \right)=x ^{-a}\]and\[x ^{a}x ^{b}=x ^{a+b}\]
|dw:1336094932499:dw| that is how it should look
they got u pfenn1
@cesar2462, don't really appreciate the attitude. There are several ways to look at this problem and sometimes different ways can help someone understand it better. We are trying to help people learn, not just get the answer.
@pfenn1 i like the idea how you separate it into sections can you do it again with another problem
sure
-56 TIMES A 4thpower TIMES X 4thpower over -8 TIMES A 3rdpower TIMES X
\[-56A ^{4}x ^{4}\over -8A ^{3}x\]
-56A^4X^4/-8A^3X that what you mean?
Sorry, I had problems with my computer.\[\left( -56 \over-8 \right)\left( A ^{4}\over A^{3} \right)\left( x ^{4}\over x\right)=\]
thank you everyone but this medal goes @pfenn1
Thanks.
@cesar2462 The attitude is not necessary. If you have nothing nice to say, say nothing at all.
i agree^

Not the answer you are looking for?

Search for more explanations.

Ask your own question