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Let us suppose he is sold x number of one type of calendar @ a price of $2.50 so he sold (64-x) number of calenders @ a price of $ 1.75 \[$2.50x + $1.75(64-x) = $ 140.50\] now solve for x
So would #1 be 38 & #2 be 26?
i dont know i have not calculated it u cross check your answer by plugging value of x in the equation
Ok. thats the answers i got. & they worked.
YAY you did it !!!!!!!!
Can you help me with a few more?
yeah post it
With the wind, a jet takes 3 hours to fly 1890 miles. Against wind, it takes 4 hours for the same trip. Find the winds speed and the planes speed. (Let p=planes speed & w= winds speed.
if speed is p+w the plane travels 1890 miles in 3 hours if speed is p-w the plane travels 1890 miles in 4 hours now solve it
Ok, thank you. I can solve it from there. (: Next one: Flying against the wind, an airplane travels 2880 miles in 4.5 hours. Flying with the wind, the airplane can travel the same distance in 4 hours. 1. Find the speed of the plane in calm air. 2. Find the speed of the wind.
same problem as before
I just have problems with setting up the equations.
By the way, for the previous problem, the simpler equations are: x = Calendar 1 y = Calendar 2 (calendar amount) x + y = 64 (calendar cost) 2.50x + 1.75y = 140.50
Can you help me with the last one i posted?
It makes no sense to work with an equation if you can't explain what the equation means.
& half the time you dont make since. Sorry, but with all do respect, i dont like you, one bit.
& you should consider changing your name from HERO, cause your not! sorry.
Wow, really? What did I do to you?
Your all the time butting in when someone else is helping me, and you throw in your 2 cents, and half the time you make NO SINCE!
Usually people do that to me. Funny that you're saying it about me. I allowed the other person to explain. Then I "butted in" afterward.
Well how about you change your name to MR. BUTT-IN.
Perhaps a visual diagram would help, but understand that both problems are related to each other only because they are systems of equations. Other than that, they are two completely different problems.
As far as my explanation, I can take another stab at it to make it super clear. If it isn't clear after that, then I won't bother you anymore.
Look im sorry, i really aint got time to bulll crap around, i got finals Monday for 2 different maths, and im freakin out!
It is easier to work with variables then entire expressions, so we usually define x = number of 1st calendar type y = number of 2nd calendar type The problem states that there are a total of 64 calendars, so: Calendar 1 + Calendar 2 = 64 || || x + y = 64 The problem states that 1 calendar costs 2.50 each. The other costs 1.75 each: Calendar 1 costs 2.50 each Calendar 2 costs 1.75 each The total amount of calendars sold costs 140.50. In other words, when all 64 calendars together are sold the total cost will be 140.50: 2.50(Calendar 1) + 1.75(Calendar 2) = 140.50 || || 2.50 x + 1.75 y = 140.50 So now, all we do is write both equations together as a system of equations: x + y = 64 2.50x + 1.75y = 140.50 Try to keep in mind what x and y means as you observe these equations.
Please try to control your frustration. It is counter-productive to studying.
@pamelaa23 hero is right you should try to understand the thing.........but that was hillarious Mr. Butt-In
Lol, i know. But, i thought after that problem i was caught up on work and everything. & then a friends text me and reminded me about our other work. * turns out its due tomorrow, 75 questions of Trig/Algebra & a bunch more work.