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Pamelaa23

Mickey sold two types of calendars for her club. She sold a total of 64 calendars for $140.50. One type of calendar sold for $2.50 each, and the other sold for $1.75 each. 1. How many of the $2.50 calendars did she sell? 2. How many of the $1.75 calendars did she sell?

  • one year ago
  • one year ago

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  1. sheg
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    Let us suppose he is sold x number of one type of calendar @ a price of $2.50 so he sold (64-x) number of calenders @ a price of $ 1.75 \[$2.50x + $1.75(64-x) = $ 140.50\] now solve for x

    • one year ago
  2. Pamelaa23
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    So would #1 be 38 & #2 be 26?

    • one year ago
  3. sheg
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    i dont know i have not calculated it u cross check your answer by plugging value of x in the equation

    • one year ago
  4. Pamelaa23
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    Ok. thats the answers i got. & they worked.

    • one year ago
  5. sheg
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    YAY you did it !!!!!!!!

    • one year ago
  6. Pamelaa23
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    Can you help me with a few more?

    • one year ago
  7. sheg
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    yeah post it

    • one year ago
  8. Pamelaa23
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    With the wind, a jet takes 3 hours to fly 1890 miles. Against wind, it takes 4 hours for the same trip. Find the winds speed and the planes speed. (Let p=planes speed & w= winds speed.

    • one year ago
  9. sheg
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    if speed is p+w the plane travels 1890 miles in 3 hours if speed is p-w the plane travels 1890 miles in 4 hours now solve it

    • one year ago
  10. Pamelaa23
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    Ok, thank you. I can solve it from there. (: Next one: Flying against the wind, an airplane travels 2880 miles in 4.5 hours. Flying with the wind, the airplane can travel the same distance in 4 hours. 1. Find the speed of the plane in calm air. 2. Find the speed of the wind.

    • one year ago
  11. sheg
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    same problem as before

    • one year ago
  12. Pamelaa23
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    I just have problems with setting up the equations.

    • one year ago
  13. Hero
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    By the way, for the previous problem, the simpler equations are: x = Calendar 1 y = Calendar 2 (calendar amount) x + y = 64 (calendar cost) 2.50x + 1.75y = 140.50

    • one year ago
  14. Pamelaa23
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    Can you help me with the last one i posted?

    • one year ago
  15. Hero
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    It makes no sense to work with an equation if you can't explain what the equation means.

    • one year ago
  16. Pamelaa23
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    & half the time you dont make since. Sorry, but with all do respect, i dont like you, one bit.

    • one year ago
  17. Pamelaa23
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    & you should consider changing your name from HERO, cause your not! sorry.

    • one year ago
  18. Hero
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    Wow, really? What did I do to you?

    • one year ago
  19. Pamelaa23
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    Your all the time butting in when someone else is helping me, and you throw in your 2 cents, and half the time you make NO SINCE!

    • one year ago
  20. Hero
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    Usually people do that to me. Funny that you're saying it about me. I allowed the other person to explain. Then I "butted in" afterward.

    • one year ago
  21. Pamelaa23
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    Well how about you change your name to MR. BUTT-IN.

    • one year ago
  22. Hero
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    Perhaps a visual diagram would help, but understand that both problems are related to each other only because they are systems of equations. Other than that, they are two completely different problems.

    • one year ago
  23. Hero
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    As far as my explanation, I can take another stab at it to make it super clear. If it isn't clear after that, then I won't bother you anymore.

    • one year ago
  24. Pamelaa23
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    Look im sorry, i really aint got time to bulll crap around, i got finals Monday for 2 different maths, and im freakin out!

    • one year ago
  25. Hero
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    It is easier to work with variables then entire expressions, so we usually define x = number of 1st calendar type y = number of 2nd calendar type The problem states that there are a total of 64 calendars, so: Calendar 1 + Calendar 2 = 64 || || x + y = 64 The problem states that 1 calendar costs 2.50 each. The other costs 1.75 each: Calendar 1 costs 2.50 each Calendar 2 costs 1.75 each The total amount of calendars sold costs 140.50. In other words, when all 64 calendars together are sold the total cost will be 140.50: 2.50(Calendar 1) + 1.75(Calendar 2) = 140.50 || || 2.50 x + 1.75 y = 140.50 So now, all we do is write both equations together as a system of equations: x + y = 64 2.50x + 1.75y = 140.50 Try to keep in mind what x and y means as you observe these equations.

    • one year ago
  26. Hero
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    Please try to control your frustration. It is counter-productive to studying.

    • one year ago
  27. sheg
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    @pamelaa23 hero is right you should try to understand the thing.........but that was hillarious Mr. Butt-In

    • one year ago
  28. Pamelaa23
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    Lol, i know. But, i thought after that problem i was caught up on work and everything. & then a friends text me and reminded me about our other work. * turns out its due tomorrow, 75 questions of Trig/Algebra & a bunch more work.

    • one year ago
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