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countonme123

  • 2 years ago

is x to the 0 power = 1?

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  1. KingGeorge
    • 2 years ago
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    In most cases. If \(x=0\) then we have some problems.

  2. Agentjamesbond007
    • 2 years ago
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    Anything to the power of 0 is 1

  3. countonme123
    • 2 years ago
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    ok thanks guys

  4. KingGeorge
    • 2 years ago
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    Agent is right, except for when \(x=0\). Even complex numbers go to 1. \[0^0\] however is indeterminate.

  5. countonme123
    • 2 years ago
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    ok i believe you have earned a medal thanks

  6. lgbasallote
    • 2 years ago
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    i think \(\infty ^0\) is not defined is it @KingGeorge ?

  7. TuringTest
    • 2 years ago
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    @KingGeorge 's exception is an important one and yes @lgbasallote

  8. KingGeorge
    • 2 years ago
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    But infinity isn't a number (techincally), and we're assuming (at least I was) that x is a number.

  9. countonme123
    • 2 years ago
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    that is a good exception will keep in mind

  10. countonme123
    • 2 years ago
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    thanks for the discussion everyone

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