countonme123
is x to the 0 power = 1?



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KingGeorge
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In most cases. If \(x=0\) then we have some problems.

Agentjamesbond007
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Anything to the power of 0 is 1

countonme123
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ok thanks guys

KingGeorge
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Agent is right, except for when \(x=0\). Even complex numbers go to 1. \[0^0\] however is indeterminate.

countonme123
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ok i believe you have earned a medal thanks

lgbasallote
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i think \(\infty ^0\) is not defined is it @KingGeorge ?

TuringTest
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@KingGeorge 's exception is an important one
and yes @lgbasallote

KingGeorge
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But infinity isn't a number (techincally), and we're assuming (at least I was) that x is a number.

countonme123
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that is a good exception will keep in mind

countonme123
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thanks for the discussion everyone