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KingGeorgeBest ResponseYou've already chosen the best response.2
In most cases. If \(x=0\) then we have some problems.
 one year ago

Agentjamesbond007Best ResponseYou've already chosen the best response.1
Anything to the power of 0 is 1
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Agent is right, except for when \(x=0\). Even complex numbers go to 1. \[0^0\] however is indeterminate.
 one year ago

countonme123Best ResponseYou've already chosen the best response.1
ok i believe you have earned a medal thanks
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i think \(\infty ^0\) is not defined is it @KingGeorge ?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
@KingGeorge 's exception is an important one and yes @lgbasallote
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
But infinity isn't a number (techincally), and we're assuming (at least I was) that x is a number.
 one year ago

countonme123Best ResponseYou've already chosen the best response.1
that is a good exception will keep in mind
 one year ago

countonme123Best ResponseYou've already chosen the best response.1
thanks for the discussion everyone
 one year ago
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