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KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2In most cases. If \(x=0\) then we have some problems.

Agentjamesbond007
 2 years ago
Best ResponseYou've already chosen the best response.1Anything to the power of 0 is 1

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2Agent is right, except for when \(x=0\). Even complex numbers go to 1. \[0^0\] however is indeterminate.

countonme123
 2 years ago
Best ResponseYou've already chosen the best response.1ok i believe you have earned a medal thanks

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0i think \(\infty ^0\) is not defined is it @KingGeorge ?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.0@KingGeorge 's exception is an important one and yes @lgbasallote

KingGeorge
 2 years ago
Best ResponseYou've already chosen the best response.2But infinity isn't a number (techincally), and we're assuming (at least I was) that x is a number.

countonme123
 2 years ago
Best ResponseYou've already chosen the best response.1that is a good exception will keep in mind

countonme123
 2 years ago
Best ResponseYou've already chosen the best response.1thanks for the discussion everyone
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