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countonme123
 2 years ago
Best ResponseYou've already chosen the best response.1(3AB+Asquared +Bsquared) + (4Bsquared  3AB + 3Asquared)

countonme123
 2 years ago
Best ResponseYou've already chosen the best response.1can you guys help me

AccessDenied
 2 years ago
Best ResponseYou've already chosen the best response.1\((3AB + A^2 + B^2) + (4B^2  3AB + 3A^2)\) Add together liketerms. \(kA^2 + hA^2 = (k + h)A^2\), \(kAB + hAB = (k + h)AB\), etc.

AccessDenied
 2 years ago
Best ResponseYou've already chosen the best response.1You can reorder the expression using the commutative and associative properties of addition (nothing multiplied to the parentheses, its just addition so we can remove them): \((3AB  3AB) + (A^2 + 3A^2) + (B^2 + 4B^2)\) Then you just add the coefficients together. Makes sense?

AccessDenied
 2 years ago
Best ResponseYou've already chosen the best response.1Then by factoring: \((3  3)AB + (1 + 3)A^2 + (1+4)B^2\) Simplifying, we get \(0AB + 4A^2 + 5B^2 \\ = \mathbf{4A^2 + 5B^2}\)

countonme123
 2 years ago
Best ResponseYou've already chosen the best response.1yah thats right i get it thanks

AccessDenied
 2 years ago
Best ResponseYou've already chosen the best response.1The less rigorous approach is pretty much just looking at the like terms, usually faster than doing the "pair the like terms, factor, and simplify" stuff: Once you simplify it to only addition and subtractions: \(\color{green}{3AB} + \color{purple}{A^2} + \color{red}{B^2} + \color{red}{4B^2} \color{green}{ 3AB} + \color{purple}{3A^2}\) The \(3AB\) and \(3AB\) cancel, add coefficients of \(A^2\) and \(B^2\) terms You're welcome. :)
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