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countonme123

help with polynomials?

  • one year ago
  • one year ago

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  1. countonme123
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    (3AB+Asquared +Bsquared) + (4Bsquared - 3AB + 3Asquared)

    • one year ago
  2. alexwee123
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    hunger games :D

    • one year ago
  3. countonme123
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    :)

    • one year ago
  4. countonme123
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    can you guys help me

    • one year ago
  5. AccessDenied
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    \((3AB + A^2 + B^2) + (4B^2 - 3AB + 3A^2)\) Add together like-terms. \(kA^2 + hA^2 = (k + h)A^2\), \(kAB + hAB = (k + h)AB\), etc.

    • one year ago
  6. AccessDenied
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    You can reorder the expression using the commutative and associative properties of addition (nothing multiplied to the parentheses, its just addition so we can remove them): \((3AB - 3AB) + (A^2 + 3A^2) + (B^2 + 4B^2)\) Then you just add the coefficients together. Makes sense?

    • one year ago
  7. countonme123
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    it helps a bit

    • one year ago
  8. AccessDenied
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    Then by factoring: \((3 - 3)AB + (1 + 3)A^2 + (1+4)B^2\) Simplifying, we get \(0AB + 4A^2 + 5B^2 \\ = \mathbf{4A^2 + 5B^2}\)

    • one year ago
  9. countonme123
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    yah thats right i get it thanks

    • one year ago
  10. AccessDenied
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    The less rigorous approach is pretty much just looking at the like terms, usually faster than doing the "pair the like terms, factor, and simplify" stuff: Once you simplify it to only addition and subtractions: \(\color{green}{3AB} + \color{purple}{A^2} + \color{red}{B^2} + \color{red}{4B^2} \color{green}{- 3AB} + \color{purple}{3A^2}\) The \(3AB\) and \(-3AB\) cancel, add coefficients of \(A^2\) and \(B^2\) terms You're welcome. :)

    • one year ago
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