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countonme123 Group TitleBest ResponseYou've already chosen the best response.1
(3AB+Asquared +Bsquared) + (4Bsquared  3AB + 3Asquared)
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.0
hunger games :D
 2 years ago

countonme123 Group TitleBest ResponseYou've already chosen the best response.1
can you guys help me
 2 years ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
\((3AB + A^2 + B^2) + (4B^2  3AB + 3A^2)\) Add together liketerms. \(kA^2 + hA^2 = (k + h)A^2\), \(kAB + hAB = (k + h)AB\), etc.
 2 years ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
You can reorder the expression using the commutative and associative properties of addition (nothing multiplied to the parentheses, its just addition so we can remove them): \((3AB  3AB) + (A^2 + 3A^2) + (B^2 + 4B^2)\) Then you just add the coefficients together. Makes sense?
 2 years ago

countonme123 Group TitleBest ResponseYou've already chosen the best response.1
it helps a bit
 2 years ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
Then by factoring: \((3  3)AB + (1 + 3)A^2 + (1+4)B^2\) Simplifying, we get \(0AB + 4A^2 + 5B^2 \\ = \mathbf{4A^2 + 5B^2}\)
 2 years ago

countonme123 Group TitleBest ResponseYou've already chosen the best response.1
yah thats right i get it thanks
 2 years ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
The less rigorous approach is pretty much just looking at the like terms, usually faster than doing the "pair the like terms, factor, and simplify" stuff: Once you simplify it to only addition and subtractions: \(\color{green}{3AB} + \color{purple}{A^2} + \color{red}{B^2} + \color{red}{4B^2} \color{green}{ 3AB} + \color{purple}{3A^2}\) The \(3AB\) and \(3AB\) cancel, add coefficients of \(A^2\) and \(B^2\) terms You're welcome. :)
 2 years ago
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