Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
uhmmm so let me get this straight...improper integrals are solved like normal integrals then plug in values of infinity and the thingies??? @lalaly
 one year ago
 one year ago
uhmmm so let me get this straight...improper integrals are solved like normal integrals then plug in values of infinity and the thingies??? @lalaly
 one year ago
 one year ago

This Question is Closed

medisynergiBest ResponseYou've already chosen the best response.2
You have to evaluate the limits.
 one year ago

ladiesman123Best ResponseYou've already chosen the best response.0
yeah...i evaluate it like any other integrals then plugin the limits right?
 one year ago

medisynergiBest ResponseYou've already chosen the best response.2
Yes, they are solved like normal integrals. assuming the functions are continuous.
 one year ago

RohangrrBest ResponseYou've already chosen the best response.2
Comparison Test for Improper Integrals Now that we’ve seen how to actually compute improper integrals we need to address one more topic about them. Often we aren’t concerned with the actual value of these integrals. Instead we might only be interested in whether the integral is convergent or divergent. Also, there will be some integrals that we simply won’t be able to integrate and yet we would still like to know if they converge or diverge. To deal with this we’ve got a test for convergence or divergence that we can use to help us answer the question of convergence for an improper integral. We will give this test only for a subcase of the infinite interval integral, however versions of the test exist for the other subcases of the infinite interval integrals as well as integrals with discontinuous integrands. http://tutorial.math.lamar.edu/Classes/CalcII/ImproperIntegralsCompTest.aspx
 one year ago

ladiesman123Best ResponseYou've already chosen the best response.0
@medisynergi how do i know if it is continuous..and @Rohangrr what? you lost me :p
 one year ago

medisynergiBest ResponseYou've already chosen the best response.2
By definition. for example  x  has to be evaluated separately on the inerval \inf to \inf
 one year ago

medisynergiBest ResponseYou've already chosen the best response.2
1/ (1  x ) is not defined at x = 1. It is not continuous at that point. so the interval 0 to \inf would make no sense.
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.0
@Rohangrr: Why do you think that is relevant here?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.