A community for students.
Here's the question you clicked on:
 0 viewing
anjali_pant
 2 years ago
CONTINUITY QUESTION :
Examine the continuity of the function :
f(x)= ( 2[x] )/ ( 3xx ) at x=1/2 and x=1
anjali_pant
 2 years ago
CONTINUITY QUESTION : Examine the continuity of the function : f(x)= ( 2[x] )/ ( 3xx ) at x=1/2 and x=1

This Question is Closed

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0In order to get the best possible answers, it is helpful if you say in what your thoughts on it are so far; this will prevent people from telling you things you already know, and help them write their answers at an appropriate level.

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Well said @FoolForMath ! :p

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0I know, I am so amazing ;)

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Oh please ! WAKE UP ! :P

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Anyways , I will believe that you are SUPERDUPER AMAZING , only when you will SOLVE THIS question ! :p And please no direct answers , the whole explanation is required :p

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0who said I need your credence? :P

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1A FRIEND IN NEED IS A FRIEND INDEED ! So no "faaltu" baatein, help ! :p

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry, I don't do baby sitting :P

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Now from where on this earth "baby sitting" came ? Iam asking you to help me solve an ECO(H) , 2nd year maths question , not to sing a lullaby ! :p Had hai matlab ! ;p

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Thanks for honouring me with your MEDAL ! :P

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Anyways I gtg now , hope to see the answer posted ! :p Cya ! :)

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.0You should not worr y about the denominator. It is continious at any x except at x=0. All you have to examine is the function g(x) = [x]. Where is the function g(x) discontinuous?

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.0See for example http://mathworld.wolfram.com/IntegerPart.html

strenesmee
 2 years ago
Best ResponseYou've already chosen the best response.0check right and left limits at x=1/2 and x=1 If right limits are equal to left limits the function is continuous

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Iam not able to deal with [x] ! :( When there is a positive number inside [x] , that's ok with me , but when there is a negative number , Iam not able to apply the left/right hand limit ! Please help

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0[1.5] = 2. More formally, \[ \lfloora \rfloor =  \lceil a \rceil \]

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.0You do not have negative numbers now, you have 1 and 1/2

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Ok apply LHL to [x] where x>1/2

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.0I did not see the . I need better glasses.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0[ 1/2 ] = [0.5]=1

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.0[x} is constant at any open interval having end points n, n+1 or n is a positive or negative integer.

eliassaab
 2 years ago
Best ResponseYou've already chosen the best response.0so 1/2 is in the interval (1,0). Is {x] continuous at 1/2?

anjali_pant
 2 years ago
Best ResponseYou've already chosen the best response.1Heya ! Iam finally through with this question. So before closing this question , I would like to thank all of you" THANK YOU !" :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.