anonymous
  • anonymous
Use the data to make da box and wisker plot. Student heights (in) are: 60,66,59,67,68,63,62,61,69,64,61. Refer to ur box and whisker plot to answer the following questions. 1. What is the median height? 2. Between whgat heights do 50% of the students fall?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
im wondering, if we subtract the smallest value from the rest of them if the results are the same ....
amistre64
  • amistre64
it would make the numbers less scary; and moving the box itself while keeping its same dimensions shouldnt effect the outcome if im thinking about it correctly
anonymous
  • anonymous
the median you can find by putting them in order least to greatest and the middle number is the median

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
the last part I'm assuming they want the average
anonymous
  • anonymous
so add them all together and divide them by the amount of terms (11).
anonymous
  • anonymous
thanks :)
anonymous
  • anonymous
no problem :)
anonymous
  • anonymous
add me??
anonymous
  • anonymous
oh yea when finding the median make sure that if theres two of the same terms like 61, and 61 instead of putting 2 61s just put 1 :)
anonymous
  • anonymous
two or more of the same terms :)
anonymous
  • anonymous
i got both correct thanks to you

Looking for something else?

Not the answer you are looking for? Search for more explanations.