anonymous
  • anonymous
How many four-letter arrangements are possible from the four-letters given below? MNOR A. 24 B. 8 C. 32 D. 4
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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brinazarski
  • brinazarski
I think it's A, however, you'll want someone to confirm that for you. This is because it would be 4!, therefore 4 x 3 x 2 x 1, which is 24, and since there are no repeated letters, nothing needs to be divided.
anonymous
  • anonymous
Factorial 4
anonymous
  • anonymous
Yup, @brinazarski is correct. It's 4!, no repeated letters and any permutation is valid.

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brinazarski
  • brinazarski
Thanks for the medal guys :)

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