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Like normal division, what would you need to multiply (r+2) by to get close to (r^6+0r-64)?
idk i dont know how can you explain
If I gave you this:|dw:1336153681989:dw| How would you go about solving it?
You would say, "what is the largest number I can multiply 6 by to get the first number?" Since 6 is greater than 4 you would ask the question again about 42. The same logic applies to your problem... What do I need to multiply 'r' by to get r^6?|dw:1336153892815:dw|
\[ r^6-64=(r-2) (r+2) \left(r^2-2 r+4\right) \left(r^2+2 r+4\right) \] You can also factor before if it is permitted. Division will be easy by r+2
Not even sure if basic division makes sense at this point. :p
to be fair, 6 *n = 4 when n=4/6 :)
notice that when we want to zero out the first term; we multiply by that term divded by the one on the outside same pattern applies to polys
ok but i get the positive and negatives mixed up
i get positives and negatives mixed up to, which is why i always have to dbl or trpl chk my outcomes
the key being, the top is just the division of the first terms each time till you decide to stop
usually you simplfy the top as you go tho and wouldnt leave it in that structure
its no different form what they taught you back in the 3rd or 4th grade :) you just gotta practice it to get more confident at it, but theres nothing new to it overall
i wish it was like that for me but i get the numbers right just wrong signs :(
wrong signs tend to be a result of forgeting that you are subtracting everything; just like normal: 8 -------- 4 ) 34 8(4) = 32 do we add or subtract the 32 to get the next line?
subtract i believe
correct, and its the same basic concept when using polys to; division is division no matter what you use