## anonymous 4 years ago Use the quadratic formula to find the zeros of the function y = 2x2 + 3x + 6. Round to the nearest tenth if necessary. A. {-1.7, 2.3} B. {-2.4, 2.4} C. {-2.3, 0.8} D. no real solution

1. anonymous

a=2; b=3; c=6 formula is $-b \pm \sqrt{b ^{2}-4ac}$/2a solve!!

2. anonymous

$-b \pm \sqrt{b ^{2}-4ac}/2a$

3. anonymous

$\LARGE {x_{1/2}} = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$

4. anonymous

so for this one: $-3\pm \sqrt{-39}/4$ there is no real solution b/c you cannot solve the sq. root of -39!!

5. anonymous

ok

6. anonymous

There is no actual solution