## laura082412 Group Title [(8 × 4) − 10]^2 + 9 2 years ago 2 years ago

1. suzy4321

if your simplifying then its 493

2. sheg

laura do you know how to solve it??

3. laura082412

no

4. sheg

Do you know the BODMAS rule

5. sheg

B- Bracket O- Over D- Divide M- Multiply A- Add S- Subtract

6. UnkleRhaukus

$[(8 × 4) − 10]^2 + 9$$=[32 − 10]^2 + 9$$=[22]^2+9$$=484+9$$=493$

7. sheg

also O can be replaced by E- Exponential

8. laura082412

ok now i get it

9. sheg

in your problem you are having $\large{[(8\times4)-10]^2+9}$

10. sheg

so first do the bracket operations so first bracket operation would be $\large{[(8\times4)-10]^2 + 9}$ $=\large{[(32)-10]^2 + 9}$ Now remove the bracket so you will have $=\large{[32-10]^2 + 9}$ now do the large brackets operation $=\large{[22]^2 + 9}$ $=\large{484 + 9}$ $=\large{493}$

11. laura082412

ok now i get it