## Chiomatn93 Group Title solve for x. 2 years ago 2 years ago

1. Chiomatn93 Group Title

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2. Australopithecus Group Title

or you could just go (x-3)(x-7) = (x-5)(x+2) + (x-5)

3. maheshmeghwal9 Group Title

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4. Australopithecus Group Title

now expand and simplify

5. maheshmeghwal9 Group Title

Now Simplify & solve. Can you do it now?

6. UnkleRhaukus Group Title

$\frac{x-3}{x-5}=\frac{x+2}{x-7}+1$ $\frac{x-3}{x-5}-\frac{x+2}{x-7}-1=0$ $=\frac{(x-7)(x-3)}{(x-7)(x-5)}-\frac{(x-5)(x+2)}{(x-5)(x-7)}-\frac{(x-5)(x-7)}{(x-5)(x-7)}$ $=\frac{(x-7)(x-3)-(x-5)(x+2)-(x-5)(x-7)}{(x-7)(x-5)}$

7. Chiomatn93 Group Title

solve for x!!!

8. Australopithecus Group Title

What are you having problems with exactly? do you know how to simplify equations at all?

9. Australopithecus Group Title

(x-3)(x-7) = (x-5)(x+2) + (x-5) = x^(2) - 10x + 21 = x^(2) - 3x - 10 = Im sure you can solve it from here but if you dont know how I got (x-3)(x-7) = (x-5)(x+2) + (x-5) from your original problem then say so

10. Australopithecus Group Title

I have no idea what the other people are doing in this problem :l

11. sheg Group Title

have u understood how to solve this problem???

12. Australopithecus Group Title

x^(2) - 10x + 21 = x^(2) - 3x - 10 = -10x + 3x = -10 - 21 = -7x = -31 x = -31/-7 = x = 31/7

13. Australopithecus Group Title

that is your answer the rest of the people who attempted this problem need a refresher on algebra and solving equations or they just did things the long way

14. Chiomatn93 Group Title

okay thanks so much lol..

15. Australopithecus Group Title

do you have any idea how I solved this? If you want me to show you how I can.

16. Chiomatn93 Group Title

yes please... im not the sharpest knife in the drawer when it comes to mathematics!

17. Australopithecus Group Title

well first you always want to bring all x terms into the numerator so to do this I multiplied both sides of the equation by (x-5) and (x-7) so (x-3)(x-5)(x-7)/(x-5) = (1 + (x+2)/(x-7)) * (x-5)(x-7) = (x-3)(x-7)(1) = (x-5)(x-7) + (x-5)(x-7)(x+2)/(x-7) = (x-3)(x-7) = (x-5)(x-7) + (x-5)(x+2)(1) = (x-5)(x-7) + (x-5)(x-7)(x+2) = (x-5)(x-7) + (x-5)(x+2) = Now expand everything Looks like I made a mistake :S

18. Australopithecus Group Title

in my previous answer

19. Australopithecus Group Title

ugh my brain it is dead. (x-3)(x-5)(x-7)/(x-5) = (1 + (x+2)/(x-7)) * (x-5)(x-7) = (x-3)(x-7)(1) = (x-5)(x-7) + (x-5)(x-7)(x+2)/(x-7) = (x-3)(x-7) = (x-5)(x-7) + (x-5)(x+2)(1) = (x-3)(x-7) = (x-5)(x-7) + (x-5)(x+2) Now expand and simplify to get the answer

20. Australopithecus Group Title

collect all x terms on one side of the equation and move all plain numbers on the other side of the equation

21. Australopithecus Group Title

this problem is quadratic so yeah there are two solutions https://www.wolframalpha.com/input/?i=%28x-3%29%28x-7%29+%3D+%28x-5%29%28x-7%29+%2B+%28x-5%29%28x%2B2%29

22. Chiomatn93 Group Title

alright thanks a bunch!