## anonymous 4 years ago Anyone please HELP me How to find the volume of the solid S from: a right circular cone with height h and base radius r

1. anonymous

1/2base*height?

2. anonymous

where base is $pi*r^2$

3. anonymous

woops I was actually close The real answer is $1/3 * pi * r^2 * h$

4. anonymous

My first guess (which was wrong) came from my udnerstanding that a the area of a right triangle is the 1/2 base * height. I then know that the base is circular so the base will be pi*r^2 Note that ANY volume will require an area times a height.

5. anonymous

What I try is.. as it was found that $r = \sqrt{c ^{2}-h ^{2}}$ so the cross sectional area is A(h)= pi r^2 = pi (c^2-h^2) from the drawing.. a=0, b=h so the volume is $\int\limits_{0}^{h} A(h) dh = \int\limits_{0}^{h} pi(c^{2}-h^{2}) dh$

6. anonymous

yes the answer is 1/3∗pi∗r2∗h but my explanation is false

7. anonymous

from my previous post, when I show my work.. could you recognise which mistakes and do you hv any suggestion? thanks

8. anonymous

Idk I haven't done multi variable cal in a while