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candyfloss94

  • 4 years ago

Anyone please HELP me How to find the volume of the solid S from: a right circular cone with height h and base radius r

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  1. Romero
    • 4 years ago
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    1/2base*height?

  2. Romero
    • 4 years ago
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    where base is \[pi*r^2\]

  3. Romero
    • 4 years ago
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    woops I was actually close The real answer is \[1/3 * pi * r^2 * h\]

  4. Romero
    • 4 years ago
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    My first guess (which was wrong) came from my udnerstanding that a the area of a right triangle is the 1/2 base * height. I then know that the base is circular so the base will be pi*r^2 Note that ANY volume will require an area times a height.

  5. candyfloss94
    • 4 years ago
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    What I try is.. as it was found that \[r = \sqrt{c ^{2}-h ^{2}}\] so the cross sectional area is A(h)= pi r^2 = pi (c^2-h^2) from the drawing.. a=0, b=h so the volume is \[\int\limits_{0}^{h} A(h) dh = \int\limits_{0}^{h} pi(c^{2}-h^{2}) dh\]

  6. candyfloss94
    • 4 years ago
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    yes the answer is 1/3∗pi∗r2∗h but my explanation is false

  7. candyfloss94
    • 4 years ago
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    from my previous post, when I show my work.. could you recognise which mistakes and do you hv any suggestion? thanks

  8. Romero
    • 4 years ago
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    Idk I haven't done multi variable cal in a while

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