At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

\((\cos x)^2 = \cos^2 x = 1 - \sin ^2 x\) i think this can be applied? but seems no :/

@lgbasallote It is not working. I already checked it.....!!

|dw:1336216786369:dw|

is dis a question?

Maybe it is doable with the Weierstrass substitution?

|dw:1336347046770:dw|

Weierstrass sub
sin x = 2t/(1+t^2)
cos x = (1-t^2)/(1+t^2)
dx = 2 dt/(1+t^2)

\[2(7\sin ^{3/2}x-3\sin ^{7/2})/21\]

No problem. :). trying to solve your problem :D

@shivam_bhalla I tried my best but failed!

Oops in part 2 of the problem, it should be
\[-\int\limits\limits_{}^{}{(2p^2-1)}dp\]

@shivam_bhalla Ok w8 I try it

@experimentX , I am getting the answer with my method :D

\( \int \cos 2x \sqrt{\sin x} dx \) <---- i guess there was error here in your method.

Yes. Sorry for the mistake in part 2 of the problem. let me correct it and tell you

Did anybody try Weierstrass substitution?

@shivam_bhalla it's ok!!! I am waiting and try Weierstrass substitution as @estudier is said

I try Weierstrass substitution

something doesn't seem right
http://www.wolframalpha.com/input/?i=integrate+2x%2Fsqrt%281+-+x^4%29

@experimentX , that is the solution for part 1. Now I am stuck at part 2 of the integration

@experimentX ,Looks like we need to learn elliptical integral.

LOL. looks like I really need to sleep now. Sorry @RedPrince .@experimentX .

sure ... let me know too.

http://www.wolframalpha.com/input/?i=integrate+sqrt%28x++-+x^3%29+dx

is it indefinite integral??

@shivam_bhalla
Yes,seems like elliptic integral is the way...

this is my assignment and I post it!

I am a student of BS Computer Science and I am 19 years old!

Ohh. LOL I am just 17 and just completed my 12th grade

Maybe it needs two substitutions.
I am surprised that they gave you such an integral.....

@shivam_bhalla me also first time I heard about elliptic integral

@satellite73 Anything spring to mind?

lol university, not college. is the university not made up of colleges?

no i am braid dead and i loathe techniques of integration. that is why they invented computers

lol

Ok. @amistre64 should help when he comes online :)

@amistre64 's profile picture itself is integration :P

(u^(1/2)(1-u^2)) du/(1-u^2)^(1/2)
Best I can do, still gives elliptic

@RedPrince , did you reconfirm the question ??

is there limits?? or just indefinite integral??

@RedPrince Yes, same question as @experimentX

I think it would be better if
t^2 = sinx
2tdt = cos x dx
\[\int\limits_{}^{}(1-t^4)(t)(2t )(dt)\]

well ... that solves our problem!!

Good work @experimentX :) By the way, sometype wrong question teaches us new things :P :D

*sometimes

yea elliptical integrals!!

@eliassaab how this answer is come

|dw:1336919117275:dw|

@mahmit2012 , yes. @RedPrince said there was typo in original question he first mentioned

|dw:1336919188247:dw|

@mahmit2012 yes you are true but how you get it!