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 2 years ago
What is the rule to get this list of ordered pairs :
(0,0),(1,1),(2,1),(3,2),(4,2),(5,3),(6,3),...
 2 years ago
What is the rule to get this list of ordered pairs : (0,0),(1,1),(2,1),(3,2),(4,2),(5,3),(6,3),...

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TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2perhaps whenever x is odd add one to y ?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2..or you want an equation?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0\(\Large \color{purple}{ 1) x + 1,y + 1 }\) \(\Large \color{purple}{ 2) x + 1, y }\) It keeps repeating.

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0and expression for the nth term.

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0Well I actually got it from a while loop, and I wanted to know if I can translate it to a mathematical expression.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0No, you have to use the programming if  else, or while  do

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2should be like (n,n/2) when n is even and (n,n/2+1) when n is odd how to combine them (you using python?)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0@TuringTest lol, Do  while is in every language

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2I ask because I am learning python and wanted tips if NoData is an expert ..sort of a separate Q

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0This is what it does: x = 0, y = 0 y = x  y x = x + 1

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry Turing I'm not a expert, I'm actually learning some Java, but I got distracted with this thing hehe.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1what you have typed up is already a recurrsive definition; and it might have to be piecewise defined to be explicit as has already been pointed out

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0There is no way of expressing it without in the piecewise way?. I'm so fool because I can't see it from the code =/

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1if you are trying to confine yourself to a limited method, your going to be limited in your results .... the piecewise functions are real and useable function ... as is it looks like y is increaseing at half the rate of x, and if you can use a ceiling or floor function to weed it up or down as needed, you might be able to code it up sufficiently with a 0,0 condition as separate

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1if we ratio it out: \[1,2,1\frac{1}{2},2,1\frac{1}{3},2,1\frac{1}{4},2,1\frac{1}{5},2,1\frac{1}{6},...\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[f(x')=1+\frac{1}{x};\ x\in Odd\]\[f(x')=2;\ x\in Even\] prolly bad notations, but the slope of each discrete point would be something like this

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.11 + 1/n maybe better; for x in Odd

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you amistre64 I'll try to understand that.

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0I just thought it would be easier to do without piecewise functions, but now I see it is not.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1computers are great with piecewises ;) good luck with it

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.2sorry noData I had to take your medal away and give it to amistre... his was the best answer :P

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0No problem TuringTest I actually was asking for an answer and that is what amistre64 gave me.

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.0Although I didn't know someone could change his mind about a medal.
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