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What is the rule to get this list of ordered pairs :
(0,0),(1,1),(2,1),(3,2),(4,2),(5,3),(6,3),...
 one year ago
 one year ago
What is the rule to get this list of ordered pairs : (0,0),(1,1),(2,1),(3,2),(4,2),(5,3),(6,3),...
 one year ago
 one year ago

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TuringTestBest ResponseYou've already chosen the best response.2
perhaps whenever x is odd add one to y ?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
..or you want an equation?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
\(\Large \color{purple}{ 1) x + 1,y + 1 }\) \(\Large \color{purple}{ 2) x + 1, y }\) It keeps repeating.
 one year ago

NodataBest ResponseYou've already chosen the best response.0
and expression for the nth term.
 one year ago

NodataBest ResponseYou've already chosen the best response.0
Well I actually got it from a while loop, and I wanted to know if I can translate it to a mathematical expression.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
No, you have to use the programming if  else, or while  do
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
should be like (n,n/2) when n is even and (n,n/2+1) when n is odd how to combine them (you using python?)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
@TuringTest lol, Do  while is in every language
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
I ask because I am learning python and wanted tips if NoData is an expert ..sort of a separate Q
 one year ago

NodataBest ResponseYou've already chosen the best response.0
This is what it does: x = 0, y = 0 y = x  y x = x + 1
 one year ago

NodataBest ResponseYou've already chosen the best response.0
Sorry Turing I'm not a expert, I'm actually learning some Java, but I got distracted with this thing hehe.
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
what you have typed up is already a recurrsive definition; and it might have to be piecewise defined to be explicit as has already been pointed out
 one year ago

NodataBest ResponseYou've already chosen the best response.0
There is no way of expressing it without in the piecewise way?. I'm so fool because I can't see it from the code =/
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
if you are trying to confine yourself to a limited method, your going to be limited in your results .... the piecewise functions are real and useable function ... as is it looks like y is increaseing at half the rate of x, and if you can use a ceiling or floor function to weed it up or down as needed, you might be able to code it up sufficiently with a 0,0 condition as separate
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
if we ratio it out: \[1,2,1\frac{1}{2},2,1\frac{1}{3},2,1\frac{1}{4},2,1\frac{1}{5},2,1\frac{1}{6},...\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
\[f(x')=1+\frac{1}{x};\ x\in Odd\]\[f(x')=2;\ x\in Even\] prolly bad notations, but the slope of each discrete point would be something like this
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
1 + 1/n maybe better; for x in Odd
 one year ago

NodataBest ResponseYou've already chosen the best response.0
Thank you amistre64 I'll try to understand that.
 one year ago

NodataBest ResponseYou've already chosen the best response.0
I just thought it would be easier to do without piecewise functions, but now I see it is not.
 one year ago

amistre64Best ResponseYou've already chosen the best response.1
computers are great with piecewises ;) good luck with it
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
sorry noData I had to take your medal away and give it to amistre... his was the best answer :P
 one year ago

NodataBest ResponseYou've already chosen the best response.0
No problem TuringTest I actually was asking for an answer and that is what amistre64 gave me.
 one year ago

NodataBest ResponseYou've already chosen the best response.0
Although I didn't know someone could change his mind about a medal.
 one year ago
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