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What are the possible number of positive, negative, and complex zeros of f(x) = 3x4  5x3  x2  8x + 4 ?
A) Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0
B) Positive: 1; Negative: 3 or 1; Complex: 2 or 0
C) Positive: 3 or 1; Negative: 1; Complex: 2 or 0
D) Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0
 one year ago
 one year ago
What are the possible number of positive, negative, and complex zeros of f(x) = 3x4  5x3  x2  8x + 4 ? A) Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 B) Positive: 1; Negative: 3 or 1; Complex: 2 or 0 C) Positive: 3 or 1; Negative: 1; Complex: 2 or 0 D) Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0
 one year ago
 one year ago

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ChukRockBest ResponseYou've already chosen the best response.1
the numbers after the x's are exponents, correct?
 one year ago

joeywhiteBest ResponseYou've already chosen the best response.0
there are 2 positive and 2 complex roots
 one year ago

joeywhiteBest ResponseYou've already chosen the best response.0
i've tried using descartes rule of signs but i got confused to be honest so i solved it
 one year ago

sahil51993Best ResponseYou've already chosen the best response.0
one root lie b/w 0 and 1
 one year ago

sahil51993Best ResponseYou've already chosen the best response.0
other will be negative as f(x) is increasing in R+
 one year ago

sahil51993Best ResponseYou've already chosen the best response.0
yeah 1 will be positive and one will not be possitive it can also be possilbe that roots may be irrational becuase irrational roots also exist in pairs
 one year ago

estudierBest ResponseYou've already chosen the best response.4
there is 1 sign change so by DRS there is 1 positive root Sub x for x to get negative roots, 3 sign changes so 3 or 1 negative roots Complex roots are total roots, 4, less positive and negative roots so 0 or 2 of those. Answer is B
 one year ago
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