Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

tien.lam12

  • 2 years ago

What are the possible number of positive, negative, and complex zeros of f(x) = -3x4 - 5x3 - x2 - 8x + 4 ? A) Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 B) Positive: 1; Negative: 3 or 1; Complex: 2 or 0 C) Positive: 3 or 1; Negative: 1; Complex: 2 or 0 D) Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0

  • This Question is Closed
  1. ChukRock
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the numbers after the x's are exponents, correct?

  2. tien.lam12
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  3. joeywhite
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there are 2 positive and 2 complex roots

  4. joeywhite
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i've tried using descartes rule of signs but i got confused to be honest so i solved it

  5. sahil51993
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    one root lie b/w 0 and 1

  6. joeywhite
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    right

  7. sahil51993
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    other will be negative as f(x) is increasing in R+

  8. sahil51993
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Am i right????

  9. joeywhite
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no 2 positive

  10. sahil51993
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah 1 will be positive and one will not be possitive it can also be possilbe that roots may be irrational becuase irrational roots also exist in pairs

  11. estudier
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 4

    there is 1 sign change so by DRS there is 1 positive root Sub -x for x to get negative roots, 3 sign changes so 3 or 1 negative roots Complex roots are total roots, 4, less positive and negative roots so 0 or 2 of those. Answer is B

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.