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tien.lam12
 3 years ago
What are the possible number of positive, negative, and complex zeros of f(x) = 3x4  5x3  x2  8x + 4 ?
A) Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0
B) Positive: 1; Negative: 3 or 1; Complex: 2 or 0
C) Positive: 3 or 1; Negative: 1; Complex: 2 or 0
D) Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0
tien.lam12
 3 years ago
What are the possible number of positive, negative, and complex zeros of f(x) = 3x4  5x3  x2  8x + 4 ? A) Positive: 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0 B) Positive: 1; Negative: 3 or 1; Complex: 2 or 0 C) Positive: 3 or 1; Negative: 1; Complex: 2 or 0 D) Positive: 4 or 2 or 0; Negative: 2 or 0; Complex: 4 or 2 or 0

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ChukRock
 3 years ago
Best ResponseYou've already chosen the best response.2the numbers after the x's are exponents, correct?

joeywhite
 3 years ago
Best ResponseYou've already chosen the best response.0there are 2 positive and 2 complex roots

joeywhite
 3 years ago
Best ResponseYou've already chosen the best response.0i've tried using descartes rule of signs but i got confused to be honest so i solved it

sahil51993
 3 years ago
Best ResponseYou've already chosen the best response.0one root lie b/w 0 and 1

sahil51993
 3 years ago
Best ResponseYou've already chosen the best response.0other will be negative as f(x) is increasing in R+

sahil51993
 3 years ago
Best ResponseYou've already chosen the best response.0yeah 1 will be positive and one will not be possitive it can also be possilbe that roots may be irrational becuase irrational roots also exist in pairs

estudier
 3 years ago
Best ResponseYou've already chosen the best response.4there is 1 sign change so by DRS there is 1 positive root Sub x for x to get negative roots, 3 sign changes so 3 or 1 negative roots Complex roots are total roots, 4, less positive and negative roots so 0 or 2 of those. Answer is B
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