anonymous
  • anonymous
y+3/2y + 5/y-1=1/2
Mathematics
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anonymous
  • anonymous
y+3/2y + 5/y-1=1/2
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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lgbasallote
  • lgbasallote
Hint: multiply every term of your equation by 2y
lgbasallote
  • lgbasallote
if you wanna know why 2y, you can check out this tutorial i once made on LCM http://openstudy.com/users/lgbasallote#/updates/4f9f93dae4b01d279f25db37
anonymous
  • anonymous
what abut the y-1?

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lgbasallote
  • lgbasallote
oh it's over y-1? i thought the 1 was a whole number...then the LCM is 2y(y-1) sorry bout that
lgbasallote
  • lgbasallote
just making sure \(\Large \frac{3}{2y} + \frac{5}{y-1} = \frac{1}{2}\) that's the problem right?
anonymous
  • anonymous
y+3 over 2y, but the rest is right
lgbasallote
  • lgbasallote
oh yeah..sorry...well the LCM is right so we multiply by 2y(y-1) \((y+3)(y-1) + 5(2y) = 1(y)(y-1)\) this will be our resulting equation won't it?
anonymous
  • anonymous
yes, thank you!

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