Prove that
\[\huge{(e^w)^z=e^{[(w+2ni\pi)(z)]}}\]
but \[\huge (e^w)^z\ne e^{(wz)}\] where w and z are complex.

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@shivam_bhalla

\[\text{ Do you recall } e^{ i \theta}= \cos(\theta) +i \sin(\theta)\]

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