anonymous
  • anonymous
factor completely: x^7-14x^6-51x^5
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
|dw:1336325178637:dw|
ParthKohli
  • ParthKohli
Find the common factor and put that outside the bracket.
pokemon23
  • pokemon23
If I'm correct

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ParthKohli
  • ParthKohli
You are correct. @pokemon23
anonymous
  • anonymous
x^5(x^2-14x-51x) ?
anonymous
  • anonymous
\[x^5(x^2-14x-51)\]
pokemon23
  • pokemon23
thanks parth nice to meet you I'ma long time user but I departed OS for three months and I'm read to rock and roll!
ParthKohli
  • ParthKohli
Oops, you got the 51x incorrect @pokemon23
ParthKohli
  • ParthKohli
\(\Large \color{purple}{\rightarrow x^5(51x) = 51x^6 }\)
anonymous
  • anonymous
\[x ^{5}\times(x-3)\times(x+17)\]
anonymous
  • anonymous
so what's the full equation?
anonymous
  • anonymous
an amir. sat has something totally different
anonymous
  • anonymous
can someone1 clarify for me plz
ParthKohli
  • ParthKohli
@endiia Amir is correct, he has actually grouped the quadratic expression.
anonymous
  • anonymous
x^2−14x−51=(x-3)*(x+17)
anonymous
  • anonymous
so when u factor it the answer is (x-3)(x+17)
anonymous
  • anonymous
so x is 3 & 17
ParthKohli
  • ParthKohli
Yes, a better and cleared answer is: \(\LARGE \color{purple}{\rightarrow x^5[(x - 3)(x + 17)] }\)
anonymous
  • anonymous
sorry it's x^2−14x−51=(x+3)*(x-17) so answer is x^5×(x+3)×(x-17)
anonymous
  • anonymous
and x is 0 & -3 & 17

Looking for something else?

Not the answer you are looking for? Search for more explanations.