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ParthKohliBest ResponseYou've already chosen the best response.1
Find the common factor and put that outside the bracket.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
You are correct. @pokemon23
 one year ago

pokemon23Best ResponseYou've already chosen the best response.1
thanks parth nice to meet you I'ma long time user but I departed OS for three months and I'm read to rock and roll!
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Oops, you got the 51x incorrect @pokemon23
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
\(\Large \color{purple}{\rightarrow x^5(51x) = 51x^6 }\)
 one year ago

amir.satBest ResponseYou've already chosen the best response.0
\[x ^{5}\times(x3)\times(x+17)\]
 one year ago

endiiaBest ResponseYou've already chosen the best response.0
so what's the full equation?
 one year ago

endiiaBest ResponseYou've already chosen the best response.0
an amir. sat has something totally different
 one year ago

endiiaBest ResponseYou've already chosen the best response.0
can someone1 clarify for me plz
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
@endiia Amir is correct, he has actually grouped the quadratic expression.
 one year ago

amir.satBest ResponseYou've already chosen the best response.0
x^2−14x−51=(x3)*(x+17)
 one year ago

endiiaBest ResponseYou've already chosen the best response.0
so when u factor it the answer is (x3)(x+17)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Yes, a better and cleared answer is: \(\LARGE \color{purple}{\rightarrow x^5[(x  3)(x + 17)] }\)
 one year ago

amir.satBest ResponseYou've already chosen the best response.0
sorry it's x^2−14x−51=(x+3)*(x17) so answer is x^5×(x+3)×(x17)
 one year ago
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