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ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Find the common factor and put that outside the bracket.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1You are correct. @pokemon23

pokemon23
 2 years ago
Best ResponseYou've already chosen the best response.1thanks parth nice to meet you I'ma long time user but I departed OS for three months and I'm read to rock and roll!

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Oops, you got the 51x incorrect @pokemon23

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\(\Large \color{purple}{\rightarrow x^5(51x) = 51x^6 }\)

amir.sat
 2 years ago
Best ResponseYou've already chosen the best response.0\[x ^{5}\times(x3)\times(x+17)\]

endiia
 2 years ago
Best ResponseYou've already chosen the best response.0so what's the full equation?

endiia
 2 years ago
Best ResponseYou've already chosen the best response.0an amir. sat has something totally different

endiia
 2 years ago
Best ResponseYou've already chosen the best response.0can someone1 clarify for me plz

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1@endiia Amir is correct, he has actually grouped the quadratic expression.

amir.sat
 2 years ago
Best ResponseYou've already chosen the best response.0x^2−14x−51=(x3)*(x+17)

endiia
 2 years ago
Best ResponseYou've already chosen the best response.0so when u factor it the answer is (x3)(x+17)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, a better and cleared answer is: \(\LARGE \color{purple}{\rightarrow x^5[(x  3)(x + 17)] }\)

amir.sat
 2 years ago
Best ResponseYou've already chosen the best response.0sorry it's x^2−14x−51=(x+3)*(x17) so answer is x^5×(x+3)×(x17)
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