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gypsi

  • 2 years ago

Please explain...

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  1. optiquest
    • 2 years ago
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    its simply, really

  2. gypsi
    • 2 years ago
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    \[6\div r ^{2}-1 -1\div2=1\div r-1\]

  3. gypsi
    • 2 years ago
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    lcd=\[(r ^{2}-1)(r+1)(2)?\]

  4. gypsi
    • 2 years ago
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    the last term is suppose to be 1/r+1

  5. asnaseer
    • 2 years ago
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    is this your question?:\[\frac{6}{r^2-1}-\frac{1}{2}=\frac{1}{r+1}\]

  6. gypsi
    • 2 years ago
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    yes

  7. asnaseer
    • 2 years ago
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    use the fact that:\[r^2-1=(r+1)(r-1)\]

  8. optiquest
    • 2 years ago
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    okay r^2-1 = (r+1)(r-1) make all the denominators match

  9. asnaseer
    • 2 years ago
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    and then multiply both sides by (r+1). that should simplify the expression.

  10. asnaseer
    • 2 years ago
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    I need to leave now - but hopefully there are plenty of people here that can assist you...

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