anonymous
  • anonymous
Suppose a study of the faculty at U.S. medical schools revealed that 37% of the faculty were women and 63% were men. Of the female faculty, 31% were full/associate professors, 46% were assistant professors, and 23% were instructors. Of the male faculty, 51% were full/associate professors, 36% were assistant professors, and 13% were instructors. If a faculty member at a U.S. medical school selected at random held the rank of full/associate professor, what is the probability that the faculty member was female?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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slaaibak
  • slaaibak
P(Female|FULL/ASSO) = P(FEMALE AND FULL/ASSO)/P(FULL/ASSO) P(Female + Asso) = 0.37 * .31 P(Full/asso) = .37 * .31 + .63 * .51
slaaibak
  • slaaibak
Meant to be P(Female + full/Asso) = 0.37 * .31
anonymous
  • anonymous
.2630733945 Thanks

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