A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
I just don't seem to be able to understand how to get the second derivative of a parametric equation. Can someone walk me through it?
anonymous
 4 years ago
I just don't seem to be able to understand how to get the second derivative of a parametric equation. Can someone walk me through it?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, my parametric equation is x=3+3t^2, y+3t^2+t^3. to find dy/dx you divide (dy/dt)/(dx/dt). Which I can do no problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For the first derivative I got for 1((3t^2)/(4t)). Which the online homework problem says is correct.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0To find the second derivative I have to find d/dt (dy/dx). I separated the two parts and got 0 for the one, of course, and then used the quotient rule on the 3t^2/4t part. Is this correct?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1a paramentric eqution is also a vector equation: r(t) = <x(t),y(t)> right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1x=3+3t^2 , y=3t^2+t^3 x'=6t , y=6t+3t r'(t) = < 6t , 6t+3t^2 > which is what youve got for the tangent

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol, I mixed two problems in what I explained, but yes, go on

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1r''(t) is just the next derivative. r''(t) = <6, 6+6t> if im reading it right

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1http://tutorial.math.lamar.edu/Classes/CalcII/ParaTangent.aspx might help

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1bout 3/4 of the way down it goes into 2nd derivative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Right, but the question is asking for it in a certain form. Here is the question:

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1you got that in a jpeg?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol, here it is in jpg

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I just sliced a portion of the window to get the picture

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{d^2y}{dx^2}=\frac{d}{dx}(\frac{dy}{dx})=\frac{\frac{d}{dt}(\frac{dy}{dx})}{\frac{dx}{dt}}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1soo dy/dx = 1+ t/2 stick this in the derivative thing for: 1/2 right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{d}{dt}(\frac{dy}{dx})\to \frac{d}{dt}(1+t/2)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, you're right. But what I have is a dy/dx = 13t^2/4t

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1or the right dy/dx .. lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, I starting typing the first, which is pretty easy when I was actually going for a second problem. But this is the spot I always get confused. With that dy/dx I would lose the one and use quotient rule to solve for 3t^2/4t, wouldn't I? But when I do that it says I got the problem wrong

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1reduce it by t and you got 3t/4 which is simpler to derive

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1not reduce ..... simplify

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh my Gosh!! I can't believe I wasn't seeing that! Thank you!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.