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LordHadesBest ResponseYou've already chosen the best response.1
x log3 = log15 x = log15/log3
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
The natural logarithm is ln not log
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
\[3^x = 15\] \[\ln 3^{3^x} =\ln 3^{15}\] \[x=15\ln3\]
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
Is that the answer you have?
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
I just didn't know what to to do. Thanks though, Roadjester.
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
Do you know the Laws of Logs?
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
They are the same for natural log, just that you use natural log for the change of base formula.
 one year ago

IsTimBest ResponseYou've already chosen the best response.0
What's the difference between natural and common logarithms? I think people may have applied the incorrect technique into my other question.
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
Well, this is the general form for log: \[\log_{a}x \] where x is a variable and a is the base. This is basically the inverse of an exponential function of the form:\[x = a^y\]. You'll notice that rather than writing the usual "y is a function of x" I have it reversed. If you're familiar with inverse functions, this shouldn't be too troublesome.
 one year ago

roadjesterBest ResponseYou've already chosen the best response.1
Now as for what the difference between \[\ln x\] and \[\log_{} x\] is, you'll notice that when I wrote log x, I had a base a. log can take on any base. The natural log is assumed to have the base of e which is approximately 2.7182818...
 one year ago
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