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shivam_bhalla

  • 2 years ago

#Simple yet not so simple qn 1) an ideal spring with spring constant k is hung from the ceiling and a block of mass M is attached to it's lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the string is a)4Mg/k b)2Mg/k c)Mg/k d)Mg/2k

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  1. chand
    • 2 years ago
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    the answer is 2mg/k

  2. goutham1995
    • 2 years ago
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    Mg/k?

  3. shivam_bhalla
    • 2 years ago
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    Good @chand . Would you mind explaining to @goutham1995 ?

  4. chand
    • 2 years ago
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    sure. when a mass attached to a spring is suddenly released, energy is conserved. in this case, spring potential energy is equal to the potential energy of spring. 1/2 kx^2 = mgx and thus x = 2mg/k

  5. Vincent-Lyon.Fr
    • 2 years ago
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    - System is conservative (ME is conserved). - In both situation, mass is at rest, hence KE = 0 and ΔKE = 0 - Gravitational PE is converted in Elastic PE hence the equation derived by chand.

  6. shivam_bhalla
    • 2 years ago
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    The common mistake which people make in such question is F = mg= kx So x = mg/k This is the mistake I wanted to point out. :)

  7. goutham1995
    • 2 years ago
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    lol..thats what i did..but why will it be wrong? if we dont consider energy, how else can we do it?

  8. shivam_bhalla
    • 2 years ago
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    @Vincent-Lyon.Fr , can you help us here please ??

  9. Vincent-Lyon.Fr
    • 2 years ago
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    Energy makes it much easier, but you can also solve it 'the hard way' using SHM equations. I will post this solution, but have no time right now.

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