anonymous
  • anonymous
#Simple yet not so simple qn 1) an ideal spring with spring constant k is hung from the ceiling and a block of mass M is attached to it's lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the string is a)4Mg/k b)2Mg/k c)Mg/k d)Mg/2k
Physics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
the answer is 2mg/k
anonymous
  • anonymous
Mg/k?
anonymous
  • anonymous
Good @chand . Would you mind explaining to @goutham1995 ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
sure. when a mass attached to a spring is suddenly released, energy is conserved. in this case, spring potential energy is equal to the potential energy of spring. 1/2 kx^2 = mgx and thus x = 2mg/k
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
- System is conservative (ME is conserved). - In both situation, mass is at rest, hence KE = 0 and ΔKE = 0 - Gravitational PE is converted in Elastic PE hence the equation derived by chand.
anonymous
  • anonymous
The common mistake which people make in such question is F = mg= kx So x = mg/k This is the mistake I wanted to point out. :)
anonymous
  • anonymous
lol..thats what i did..but why will it be wrong? if we dont consider energy, how else can we do it?
anonymous
  • anonymous
@Vincent-Lyon.Fr , can you help us here please ??
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
Energy makes it much easier, but you can also solve it 'the hard way' using SHM equations. I will post this solution, but have no time right now.

Looking for something else?

Not the answer you are looking for? Search for more explanations.