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ParthKohli
 2 years ago
How do I solve \(\text{SYSTEM OF EQUATIONS?}\)
Look below to see the tutorial.
ParthKohli
 2 years ago
How do I solve \(\text{SYSTEM OF EQUATIONS?}\) Look below to see the tutorial.

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ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.7All of us probably know onevariable equations. But, the twovariable linear equations may confuse people. In this tutorial, solving twovariable systems would be explained by substitution and elimination. \(\LARGE \color{MidnightBlue}{\text {SUBSTITUTION}}\) \(\Large \color{purple}{\rightarrow 0.45x +0.65y = 18.55 }\) \(\Large \color{purple}{\rightarrow x + y = 35 }\) Okay, now let's take any of the variables. Let's say x for the sake of convenience. Now, we just have to solve for x by subracting y from both sides, and we get: \(\Large \color{purple}{\rightarrow x = 35  y }\) Now, we'll replace x with 35  y, and we get: \(\Large \color{purple}{\rightarrow 0.45(35  y) + 0.65y = 18.55 }\) Now, we can solve the equation easily. \(\Large \color{MidnightBlue}{\text{ELIMINATION} }\) This one is again easy. You have to seek the possible ways. Let's solve the same system again! So, let's multiply the equation 'x + y = 35' by 0.45(both sides). We get: \(\Large \color{purple}{\rightarrow 0.45x + 0.45y = 15.75 }\) Subtract both equations: \(\Large \color{purple}{\rightarrow (0.45x  0.45x) + (0.65y  0.45y) = 19.25 }\) \(\Large \color{purple}{\rightarrow 0.20y = 19.25 }\) \(\Large \color{purple}{\rightarrow y = 96.25 }\) Now, we can just solve for x because we know the value of y.

Kreshnik
 2 years ago
Best ResponseYou've already chosen the best response.0@ParthKohli Is this "Tutorial" called "Collecting medals" ? lol

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2i think we need a separate section for these

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.7@satellite73 Exactly what I think.

Romero
 2 years ago
Best ResponseYou've already chosen the best response.0So we can copy and paste a link and tell the asker to come back if he/she still had more questions after reading the tutorials @satellite73

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1your tutorial is fine as is, but its missing a few important pointers. The "why" it works would be helpful. And also if you could explain the 3 possible results that can occur. The notion that we can find infinite or no consistent solution is something that tends to confuse people. And the knowledge of why these outcomes are possible explains those mysteries.

2bornot2b
 2 years ago
Best ResponseYou've already chosen the best response.0@ParthKohli excellent work! I appreciate it.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.7@amistre64 I'd certainly take care of that in the future. @2bornot2b Thank you :)

2bornot2b
 2 years ago
Best ResponseYou've already chosen the best response.0This tutorial might turn out to be quite helpful for someone searching the internet for "how to solve simultaneous equations". @amistre64 I believe parthkohli prepared it for high school level, therefore he decided to exclude that part.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.7@2bornot2b I don't know if it's high school or not, but considering that the person knows onevariable linear equations, I posted it.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0You forgot one important thing. First of all, you said system of equations. You need to limit that down to first degree 2 varibles determined. Second of all, you forgot cramers rule. Other than that, good enough.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Did you know that you can reduce AES encryption down to a "system of equations"? You claimed to solve that, xD

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.7@inkyvoyd Yes, about the Cramer's rule, I have written on the top line that I will explain it using only substitution and elimination. You see, these are two simple methods. It'd have taken hours if I'd used the cramer's rule and graphs.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Actually, cramer's rule was the fastest way to program the system of equation's solution.

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0isnt's cramer's rule linear algebra o.O

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0i like gaussjordan elimination for the record :p

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Well, my graphing calculator says so.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0Computing determinant is itself tedious.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Well, programming a computer algebra system is more tedious .

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.0When you will study numerical analysis you will understand what I meant :)

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0I will never study numerical analysis, and I will never understand zzz

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0(Neither will my Ti84Plus SE)

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0since they said the good comments already i'll be the "simon cowell" from a tutor to another one. 1) You should solve the SUBSTITUTION and ELIMINATION methods thoroughly not just end in the middle 2) You did not state WHY you multiplied 0.45 in the ELIMINATION method. 3) Inconsistency. In the ELIMINATION method you solved for y. You did not solve for y in the SUBSTITUTION method though. and again, you cut in the middle 4) You did not prove that the results of the SUBSTITUTION method and the ELIMINATION method were the same. that are all my bad comments...otherwise it was good :) deserved the medals ^_~

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0Want to see my tutorial? The answer is always no. I just bother people until they see it, then they just give medals and leave. :/ @lgbasallote

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0They never provide feedback!

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0one more thing... "Okay, now let's take any of the variables. Let's say x for the sake of convenience. Now, we just have to solve for x by subracting y from both sides" be more specific...you did not state which you used, if first equation or second equation..although that is pretty obvious when looked at the next step, these things should still not be omitted. @inkyvoyd honestly...a lot of us do not know what you're saying :p haha no offense

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0What I'm saying? look at my link! LOOOOL

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/study#/updates/4fa33e9fe4b029e9dc3409ff
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