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GoldRush18

  • 2 years ago

The roots of the equation x^2+4x+1=0 are alpha and beta. Without solving the equation

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  1. GoldRush18
    • 2 years ago
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    i. state the values of \[\alpha+ \beta and \alpha \beta\]

  2. GoldRush18
    • 2 years ago
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    ii. find the value of\[\alpha^2+\beta^2\]

  3. GoldRush18
    • 2 years ago
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    iii. find the equation whose roots are \[1 + 1 \div \alpha and 1+1 \div \beta\]

  4. maheshmeghwal9
    • 2 years ago
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    \[\alpha+\beta=-b/a=-4/1\]

  5. maheshmeghwal9
    • 2 years ago
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    \[\alpha \beta=c/a=1/1=1.\]

  6. maheshmeghwal9
    • 2 years ago
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    \[\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha \beta\] put the values

  7. GoldRush18
    • 2 years ago
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    ok

  8. GoldRush18
    • 2 years ago
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    how do i go about doing the third part

  9. maheshmeghwal9
    • 2 years ago
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    u put the roots as\[x^2-(\gamma+\delta)x+\gamma \delta=0\] where \[\delta and \gamma\] are the 3rd part's roots.

  10. GoldRush18
    • 2 years ago
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    im a bit confused

  11. maheshmeghwal9
    • 2 years ago
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    what type of conf.

  12. GoldRush18
    • 2 years ago
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    oh now i go about the third part that says find the equation because im trying to do it but not sure if its correct can i tell u the answer what i get when im finished

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