## A community for students. Sign up today

Here's the question you clicked on:

## GoldRush18 4 years ago The roots of the equation x^2+4x+1=0 are alpha and beta. Without solving the equation

• This Question is Closed
1. GoldRush18

i. state the values of $\alpha+ \beta and \alpha \beta$

2. GoldRush18

ii. find the value of$\alpha^2+\beta^2$

3. GoldRush18

iii. find the equation whose roots are $1 + 1 \div \alpha and 1+1 \div \beta$

4. maheshmeghwal9

$\alpha+\beta=-b/a=-4/1$

5. maheshmeghwal9

$\alpha \beta=c/a=1/1=1.$

6. maheshmeghwal9

$\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha \beta$ put the values

7. GoldRush18

ok

8. GoldRush18

how do i go about doing the third part

9. maheshmeghwal9

u put the roots as$x^2-(\gamma+\delta)x+\gamma \delta=0$ where $\delta and \gamma$ are the 3rd part's roots.

10. GoldRush18

im a bit confused

11. maheshmeghwal9

what type of conf.

12. GoldRush18

oh now i go about the third part that says find the equation because im trying to do it but not sure if its correct can i tell u the answer what i get when im finished

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy