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GoldRush18

The roots of the equation x^2+4x+1=0 are alpha and beta. Without solving the equation

  • one year ago
  • one year ago

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  1. GoldRush18
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    i. state the values of \[\alpha+ \beta and \alpha \beta\]

    • one year ago
  2. GoldRush18
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    ii. find the value of\[\alpha^2+\beta^2\]

    • one year ago
  3. GoldRush18
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    iii. find the equation whose roots are \[1 + 1 \div \alpha and 1+1 \div \beta\]

    • one year ago
  4. maheshmeghwal9
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    \[\alpha+\beta=-b/a=-4/1\]

    • one year ago
  5. maheshmeghwal9
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    \[\alpha \beta=c/a=1/1=1.\]

    • one year ago
  6. maheshmeghwal9
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    \[\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha \beta\] put the values

    • one year ago
  7. GoldRush18
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    ok

    • one year ago
  8. GoldRush18
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    how do i go about doing the third part

    • one year ago
  9. maheshmeghwal9
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    u put the roots as\[x^2-(\gamma+\delta)x+\gamma \delta=0\] where \[\delta and \gamma\] are the 3rd part's roots.

    • one year ago
  10. GoldRush18
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    im a bit confused

    • one year ago
  11. maheshmeghwal9
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    what type of conf.

    • one year ago
  12. GoldRush18
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    oh now i go about the third part that says find the equation because im trying to do it but not sure if its correct can i tell u the answer what i get when im finished

    • one year ago
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