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GoldRush18

  • 2 years ago

Determine the values of the real number h for which the roots of the quadratic equation 4x^2-2hx+(8-h)=0 are real.

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  1. GoldRush18
    • 2 years ago
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    i need help!!

  2. eyust707
    • 2 years ago
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    I would use the quadratic formula..

  3. GoldRush18
    • 2 years ago
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    what answers would i get

  4. eyust707
    • 2 years ago
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    you will learn that the answer is of the least importance.. What matters is the method!

  5. eyust707
    • 2 years ago
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    Ans thats what open study is all about! I teach you how if you would like.

  6. GoldRush18
    • 2 years ago
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    can u teach me please

  7. eyust707
    • 2 years ago
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    sure!

  8. eyust707
    • 2 years ago
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    have you learned the quadratic formula?

  9. GoldRush18
    • 2 years ago
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    yes i have

  10. eyust707
    • 2 years ago
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    "x equals negitive b plus or minus the square root b squared minus of four a c all over two a"

  11. GoldRush18
    • 2 years ago
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    in this case what would b the value for c

  12. eyust707
    • 2 years ago
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    \[x = (-b \pm \sqrt{b^2 - 4 *a *c})/2a\]

  13. eyust707
    • 2 years ago
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    well that equation uses this: \[ax^2 +bx +c = 0\]

  14. eyust707
    • 2 years ago
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    a is whatever is in fron of the x^2

  15. eyust707
    • 2 years ago
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    so what is a?

  16. GoldRush18
    • 2 years ago
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    a is 4

  17. eyust707
    • 2 years ago
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    b is whatever is in front of x...

  18. eyust707
    • 2 years ago
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    so what is b?

  19. GoldRush18
    • 2 years ago
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    -2

  20. eyust707
    • 2 years ago
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    what about the h? that is in front of x too!

  21. eyust707
    • 2 years ago
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    we cant get rid of that... we are ging to use it to make our analysis

  22. GoldRush18
    • 2 years ago
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    oh ok

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spraguer (Moderator)
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